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Related papers: Classical pretzel knots and left orderability

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We determine the smooth concordance order of the 3-stranded pretzel knots P(p,q,r) with p,q,r odd. We show that each one of finite order is, in fact, ribbon, thereby proving the slice-ribbon conjecture for this family of knots. As…

Geometric Topology · Mathematics 2007-08-07 Joshua Greene , Stanislav Jabuka

Examples suggest that there is a correspondence between L-spaces and 3-manifolds whose fundamental groups cannot be left-ordered. In this paper we establish the equivalence of these conditions for several large classes of such manifolds. In…

Geometric Topology · Mathematics 2011-07-26 Steven Boyer , Cameron McA. Gordon , Liam Watson

We provide explicit formulas for the Alexander polynomial of pretzel knots and establish several immediate corollaries, including the characterization of pretzel knots with a trivial Alexander polynomial. As an application, we construct a…

Geometric Topology · Mathematics 2026-03-10 Y. Belousov

We show that nontrivial classical pretzel knots L(p,q,r) are hyperbolic with eight exceptions which are torus knots. We find Conway polynomials of n-pretzel links using a new computation tree. As applications, we compute the genera of…

Geometric Topology · Mathematics 2007-07-18 Dongseok Kim , Jaeun Lee

We provide an alternative proof of a sufficient condition for the fundamental group of the $n^{th}$ cyclic branched cover of $S^3$ along a prime knot $K$ to be left-orderable, which is originally due to Boyer-Gordon-Watson. As an…

Geometric Topology · Mathematics 2015-05-27 Ying Hu

In the present paper, we will show that a $(p,q,r)$-pretzel knot has the representativity 3 if and only if $(p,q,r)$ is either $\pm(-2,3,3)$ or $\pm(-2,3,5)$. We also show that a large algebraic knot has the representativity less than or…

Geometric Topology · Mathematics 2009-11-17 Makoto Ozawa

We provide a partial classification of the 3-strand pretzel knots $K = P(p,q,r)$ with unknotting number one. Following the classification by Kobayashi and Scharlemann-Thompson for all parameters odd, we treat the remaining families with $r$…

Geometric Topology · Mathematics 2012-12-19 Dorothy Buck , Julian Gibbons , Eric Staron

We introduce an interesting class of left adequate monoids which we call pretzel monoids. These, on the one hand, are monoids of birooted graphs with respect to a natural `glue-and-fold' operation, and on the other hand, are shown to be…

Rings and Algebras · Mathematics 2024-05-02 Daniel Heath , Mark Kambites , Nóra Szakács

We investigate when a Legendrian knot in standard contact $\mathbb{R}^3$ has a non-orientable exact Lagrangian filling. We prove analogs of several results in the orientable setting, develop new combinatorial obstructions to fillability,…

Symplectic Geometry · Mathematics 2022-04-01 Linyi Chen , Grant Crider-Phillips , Braeden Reinoso , Joshua M. Sabloff , Leyu Yau

We describe a method to compute the Culler-Shalen seminorms of a knot, using the (-3,3,4) pretzel knot as an illustrative example. We deduce that the SL2(C)-character variety of this knot consists of three algebraic curves and that it…

Geometric Topology · Mathematics 2007-05-23 Thomas W. Mattman

We investigate the orderability properties of fundamental groups of 3-dimensional manifolds. Many 3-manifold groups support left-invariant orderings, including all compact P^2-irreducible manifolds with positive first Betti number. For…

Geometric Topology · Mathematics 2007-05-23 Steven Boyer , Dale Rolfsen , Bert Wiest

We show that any exceptional non-trivial Dehn surgery on a hyperbolic two-bridge knot yields a 3-manifold whose fundamental group is left-orderable. This gives a new supporting evidence for a conjecture of Boyer, Gordon and Watson.

Geometric Topology · Mathematics 2011-10-05 Adam Clay , Masakazu Teragaito

Let $M_K$ be the 2-fold branched cover of a knot $K in $S^3$. If $H_1(M_K) = {\bf Z}_3 \oplus {\bf Z}_{3^{2i}} \oplus G$ where 3 does not divide the order of $G$ then $K$ is not of order 4 in the concordance group. This obstruction detects…

Geometric Topology · Mathematics 2013-09-30 Charles Livingston , Swatee Naik

We define the property (D) for nontrivial knots. We show that the fundamental group of the manifold obtained by Dehn surgery on a knot $K$ with property (D) with slope $\frac{p}{q}\ge 2g(K)-1$ is not left orderable. By making full use of…

Geometric Topology · Mathematics 2020-04-01 Zipei Nie

We prove that an infinite family of three-strand pretzel knots is not squeezed. In particular, we show that $P(4, -3, 5)$ is not squeezed. This answers a question posed by Lewark (2024). Our proof is obtained by comparing the Rasmussen…

Geometric Topology · Mathematics 2025-11-19 Nobuo Iida , Tatsumasa Suzuki

Boyer, Gordon, and Watson have conjectured that an irreducible rational homology 3-sphere is an L-space if and only if its fundamental group is not left-orderable. Since Dehn surgeries on knots in $S^3$ can produce large families of…

Geometric Topology · Mathematics 2020-10-27 Shiyu Liang

Let K_s be a (-2,3,2s+1)-type Pretzel knot (s >= 3) and E(K_s)(p/q) be a closed manifold obtained by Dehn surgery along K_s with a slope p/q. We prove that if q>0, p/q >= 4s+7 and p is odd, then E(K_s)(p/q) cannot contain an R-covered…

Geometric Topology · Mathematics 2014-02-19 Yasuharu Nakae

There are infinitely many pretzel links with the same Alexander polynomial (actually with trivial Alexander polynomial). By contrast, in this note we revisit the Jones polynomial of pretzel links and prove that, given a natural number S,…

Geometric Topology · Mathematics 2020-11-20 R. Díaz , P. M. G. Manchón

We give a criterion for distinguishing a prime knot $K$ in $S^3$ from every other knot in $S^3$ using the finite quotients of $\pi_1(S^3\setminus K)$. Using recent work of Baldwin-Sivek, we apply this criterion to the hyperbolic knots…

Geometric Topology · Mathematics 2022-11-15 Tamunonye Cheetham-West

Let K be a knot in the 3-sphere with 2-fold branched covering space M. If for some prime p congruent to 3 mod 4 the p-torsion in the first homology of M is cyclic with odd exponent, then K is of infinite order in the knot concordance group.…

Geometric Topology · Mathematics 2007-07-24 Charles Livingston , Swatee Naik