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We consider real hyperplane arrangements whose hyperplanes are of the form $\{x_i - x_j = s\}$ for some integer $s$, which we call deformations of the braid arrangement. In 2018, Bernardi gave a counting formula for the number of regions of…

Combinatorics · Mathematics 2026-03-27 Neha Goregaokar , Aaron Lin

We establish counting formulas and bijections for deformations of the braid arrangement. Precisely, we consider real hyperplane arrangements such that all the hyperplanes are of the form $x\_i-x\_j=s$ for some integer $s$. Classical…

Combinatorics · Mathematics 2021-06-15 Olivier Bernardi

A hyperplane arrangement in $\mathbb{R}^n$ is a finite collection of affine hyperplanes. The regions are the connected components of the complement of these hyperplanes. By a theorem of Zaslavsky, the number of regions of a hyperplane…

Combinatorics · Mathematics 2023-09-12 Priyavrat Deshpande , Krishna Menon

We show new bijective proofs of previously known formulas for the number of regions of some deformations of the braid arrangement, by means of a bijection between the no-broken-circuit sets of the corresponding integral gain graphs and some…

Combinatorics · Mathematics 2014-08-26 Sylvie Corteel , David Forge , Véronique Ventos

We obtain a novel formula for characteristic polynomials of deformations of the Braid arrangement using the notion of levels of regions. As an application, we recover and strengthen results of Chen et al. on the characteristic polynomial of…

Combinatorics · Mathematics 2024-11-07 Ningxin Zhang

This paper primarily investigates a specific type of deformation of the braid arrangement $\mathcal{B}_n$ in $\mathbb{R}^n$, denoted by $\mathcal{B}_n^A$ and defined in (1.2). Let $r_l(\mathcal{B}_n^A)$ be the number of regions of level $l$…

Combinatorics · Mathematics 2024-11-19 Yanru Chen , Houshan Fu , Suijie Wang , Jinxing Yang

We describe a family of hyperplane arrangements depending on a positive integer parameter $r$, which we refer to as the $r$-braid arrangements, and which can be viewed as a generalization of the classical braid arrangement. The wonderful…

Algebraic Geometry · Mathematics 2025-06-24 Vance Blankers , Emily Clader , Iva Halacheva , Haggai Liu , Dustin Ross

We introduce ballot matrices, a signed combinatorial structure whose definition naturally follows from the generating function for labeled interval orders. A sign reversing involution on ballot matrices is defined. We show that matrices…

Combinatorics · Mathematics 2014-10-22 Anders Claesson , Stuart A. Hannah

We investigate several hyperplane arrangements that can be viewed as deformations of Coxeter arrangements. In particular, we prove a conjecture of Linial and Stanley that the number of regions of the arrangement x_i - x_j = 1, 1 \leq i<j…

Combinatorics · Mathematics 2007-05-23 Alexander Postnikov , Richard P. Stanley

We obtain an upper and lower bound for the number of reduced words for a permutation in terms of the number of braid classes and the number of commutation classes of the permutation. We classify the permutations that achieve each of these…

Combinatorics · Mathematics 2018-08-06 Susanna Fishel , Elizabeth Milićević , Rebecca Patrias , Bridget Eileen Tenner

For a labelled tree on the vertex set $[n]:=\{1,2,..., n\}$, define the direction of each edge $ij$ to be $i\to j$ if $i<j$. The indegree sequence of $T$ can be considered as a partition $\lambda \vdash n-1$. The enumeration of trees with a…

Combinatorics · Mathematics 2009-04-02 Rosena R. X. Du , Jingbin Yin

A closed-form formula is derived for the number of occurrences of matches of a multiset of patterns among all ordered (plane-planted) trees with a given number of edges. A pattern looks like a tree, with internal nodes and leaves, but also…

Discrete Mathematics · Computer Science 2020-06-30 Nachum Dershowitz

The collection of reflecting hyperplanes of a finite Coxeter group is called a reflection arrangement and it appears in many subareas of combinatorics and representation theory. We focus on the problem of counting regions of reflection…

Combinatorics · Mathematics 2023-09-01 Priyavrat Deshpande , Krishna Menon

Construction of representations of braid group generators from $N$-state vertex models provide an elegant route to study knot and link invariants. Using such a braid group representation, an algebraic formula for the link invariants was put…

High Energy Physics - Theory · Physics 2019-01-11 Saswati Dhara , Romesh K. Kaul , P. Ramadevi , Vivek Kumar Singh

We study the bounded regions in a generic slice of the hyperplane arrangement in $\mathbb{R}^n$ consisting of the hyperplanes defined by $x_i$ and $x_i+x_j$. The bounded regions are in bijection with several classes of combinatorial…

Combinatorics · Mathematics 2014-01-29 Qingchun Ren

In 1986, Shi derived the famous formula $(n+1)^{n-1}$ for the number of regions of the Shi arrangement, a hyperplane arrangement in $\mathbb{R}^n$. There are at least two different bijective explanations of this formula, one by Pak and…

Combinatorics · Mathematics 2020-08-07 Duncan Levear

The resonance arrangement $\mathcal{A}_n$ is the arrangement of hyperplanes which has all non-zero $0/1$-vectors in $\mathbb{R}^n$ as normal vectors. It is the adjoint of the Braid arrangement and is also called the all-subsets arrangement.…

Combinatorics · Mathematics 2025-05-21 Lukas Kühne

Consider a rooted binary tree with n nodes. Assign with the root the abscissa 0, and with the left (resp. right) child of a node of abscissa i the abscissa i-1 (resp. i+1). We prove that the number of binary trees of size n having exactly…

Combinatorics · Mathematics 2025-04-11 Mireille Bousquet-Mélou , Guillaume Chapuy

This work addresses an enumeration problem on weighted bi-colored plane trees with prescribed vertex data, with all vertices labeled distinctly. We give a bijection proof of the enumeration formula originally due to Kochetkov, hence…

Combinatorics · Mathematics 2026-01-13 Sicheng Lu , Yi Song

We use a sign-reversing involution to show that trees on the vertex set [n], considered to be rooted at 1, in which no vertex has exactly one child are counted by 1/n sum_{k=1}^{n} (-1)^(n-k) {n}-choose-{k} (n-1)!/(k-1)! k^(k-1). This…

Combinatorics · Mathematics 2014-07-01 David Callan
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