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We demonstrate a novel approach for the random sampling of Latin squares of order~$n$ via probabilistic divide-and-conquer. The algorithm divides the entries of the table modulo powers of $2$, and samples a corresponding binary contingency…

Computation · Statistics 2017-03-28 Stephen DeSalvo

Two $n \times n$ Latin squares $L_1, L_2$ are said to be orthogonal if, for every ordered pair $(x,y)$ of symbols, there are coordinates $(i,j)$ such that $L_1(i,j) = x$ and $L_2(i,j) = y$. A $k$-MOLS is a sequence of $k$…

Combinatorics · Mathematics 2019-10-08 Simona Boyadzhiyska , Shagnik Das , Tibor Szabó

We answer a question posed by D\'enes and Keedwell that is equivalent to the following. For each order $n$ what is the smallest size of a partial latin square that cannot be embedded into the Cayley table of any group of order $n$? We also…

Combinatorics · Mathematics 2017-01-11 Ian M. Wanless , Bridget S. Webb

A quandle is an algebraic structure satisfying three axioms: idempotency, right-invertibility and right self-distributivity. In quandles, right translations are permutations. The profile of a quandle is the list of cycle structures, one per…

Combinatorics · Mathematics 2021-12-10 António Lages , Pedro Lopes , Petr Vojtěchovský

We will show that there are at least 8, 10 and 9 mutually orthogonal Latin squares (MOLS) of orders $n=54$, $96$ and $108$. The cases $n=54$ and $96$ are obtained by constructing separable permutation codes consisting of $8 \times 54$ and…

Combinatorics · Mathematics 2024-12-03 R. Julian R. Abel , Ingo Janiszczak , Reiner Staszewski

Despite the fact that latin cubes have been studied since in the 1940's, there are only a few results on embedding partial latin cubes, and all these results are far from being optimal with respect to the size of the containing cube. For…

Combinatorics · Mathematics 2022-09-15 Amin Bahmanian

A Latin square of order $n$ is an $n \times n$ matrix of $n$ symbols, such that each symbol occurs exactly once in each row and column. For an odd prime power $q$ let $\mathbb{F}_q$ denote the finite field of order $q$. A quadratic Latin…

Combinatorics · Mathematics 2023-07-18 Jack Allsop

An algorithm that uses the cycle structure of the rows, or the columns, of a Latin square to compute its autotopy group is introduced. As a result, a bound for the size of the autotopy group is obtained. This bound is used to show that the…

Combinatorics · Mathematics 2014-07-29 Daniel Kotlar

A Latin square of side n defines in a natural way a finite geometry on 3n points, with three lines of size n and n^2 lines of size 3. A Latin square of side n with a transversal similarly defines a finite geometry on 3n+1 points, with three…

Combinatorics · Mathematics 2011-08-26 Lou M. Pretorius , Konrad J. Swanepoel

Lagrange's Four Squares Theorem states that any positive integer can be expressed as the sum of four integer squares. We investigate the analogous question over Quaternion rings, focusing on squares of elements of Quaternion rings with…

Number Theory · Mathematics 2017-04-10 Anna Cooke , Spencer Hamblen , Sam Whitfield

A Latin square of order $n$ is an $n\times n$ matrix in which each row and column contains each of $n$ symbols exactly once. For $\epsilon>0$, we show that with high probability a uniformly random Latin square of order $n$ has no proper…

Combinatorics · Mathematics 2024-05-08 Michael J. Gill , Adam Mammoliti , Ian M. Wanless

We investigate retransmission permutation arrays (RPAs) that are motivated by applications in overlapping channel transmissions. An RPA is an $n\times n$ array in which each row is a permutation of ${1, ..., n}$, and for $1\leq i\leq n$,…

Combinatorics · Mathematics 2015-05-05 Ian M. Wanless , Xiande Zhang

In this paper, we prove that for a given biquaternion algebra over a field of characteristic two, one can move from one symbol presentation to another by at most three steps, such that in each step at least one entry remains unchanged. If…

Rings and Algebras · Mathematics 2013-10-28 Adam Chapman

We prove a conjecture by Garbe et al. [arXiv:2010.07854] by showing that a Latin square is quasirandom if and only if the density of every 2x3 pattern is 1/720+o(1). This result is the best possible in the sense that 2x3 cannot be replaced…

Combinatorics · Mathematics 2021-08-27 Jacob W. Cooper , Daniel Kral , Ander Lamaison , Samuel Mohr

Magic squares are well-known arrangements of integers with common row, column, and diagonal sums. Various other magic shapes have been proposed, but triangles have been somewhat overlooked. We introduce certain triangular arrangements of…

General Mathematics · Mathematics 2022-08-29 Gabriel Hale , Bjorn Vogen , Matthew Wright

We show how to determine if a given simple rectilinear polygon can be tiled with rectangles, each having an integer side.

Combinatorics · Mathematics 2009-09-25 Richard Kenyon

It is proved that for any prescribed orientation of the triples of either a Steiner triple system or a Latin square of odd order, there exists an embedding in an orientable surface with the triples forming triangular faces and one extra…

Combinatorics · Mathematics 2019-11-19 Terry S. Griggs , Thomas A. McCourt , Jozef Siran

We consider the problem of constructing Latin cubes subject to the condition that some symbols may not appear in certain cells. We prove that there is a constant $\gamma > 0$ such that if $n=2t$ and $A$ is a $3$-dimensional $n\times n\times…

Combinatorics · Mathematics 2019-04-17 Carl Johan Casselgren , Lan Anh Pham

The Dinitz conjecture states that, for each $n$ and for every collection of $n$-element sets $S_{ij}$, an $n\times n$ partial latin square can be found with the $(i,j)$\<th entry taken from $S_{ij}$. The analogous statement for $(n-1)\times…

Combinatorics · Mathematics 2009-09-25 Jeannette C. M. Janssen

Let $m \leq n \leq k$. An $m \times n \times k$ 0-1 array is a Latin box if it contains exactly $mn$ ones, and has at most one $1$ in each line. As a special case, Latin boxes in which $m = n = k$ are equivalent to Latin squares. Let…

Combinatorics · Mathematics 2019-02-12 Zur Luria , Michael Simkin
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