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Let R be a Gorenstein local domain of dimension one. We show that a nonfree maximal Cohen--Macaulay R-module M possessing more than one nonfree indecomposable summand in the middle term of the almost split sequence ending in M has a…

Commutative Algebra · Mathematics 2019-11-12 Toshinori Kobayashi

We give a positive answer to the Huneke-Wiegand Conjecture for monomial ideals over free numerical semigroup rings, and for two generated monomial ideals over complete intersection numerical semigroup rings.

Commutative Algebra · Mathematics 2012-11-20 Pedro A. Garcia-Sanchez , Micah J. Leamer

The purpose of this note is to show that a finitely generated graded module $M$ over $S=k[x_1,\ldots,x_n]$, $k$ a field, is sequentially Cohen-Macaulay if and only if its arithmetic degree ${\rm adeg}(M)$ agrees with ${\rm adeg}(F/{\rm…

Commutative Algebra · Mathematics 2023-07-28 Giulio Caviglia , Alessandro De Stefani

Recently it has been proved that any arithmetically Cohen-Macaulay (ACM) bundle of rank two on a general, smooth hypersurface of degree at least three and dimension at least four is a sum of line bundles. When the dimension of the…

Algebraic Geometry · Mathematics 2010-05-24 Jishnu Biswas , G. V. Ravindra

Over a commutative Noetherian ring, we show that the Auslander-Reiten conjecture holds true for the class of (finitely generated) modules whose dual has finite complete intersection dimension. We provide another result that validates the…

Commutative Algebra · Mathematics 2026-03-16 Dipankar Ghosh , Mouma Samanta

We show that the property of a standard graded algebra R being Cohen-Macaulay is characterized by the existence of a pure Cohen-Macaulay R-module corresponding to any degree sequence of length at most depth(R). We also give a relation in…

Commutative Algebra · Mathematics 2017-01-24 H. Ananthnarayan , Rajiv Kumar

Let A be a commutative noetherian ring. Let H(A) be the quotient of the Grothendieck group of finitely generated A-modules by the subgroup generated by pseudo-zero modules. Suppose that the real vector space H(A)_R = H(A) \otimes_Z R has…

Commutative Algebra · Mathematics 2020-12-15 Ryo Takahashi

We introduce a new invariant for subcategories X of finitely generated modules over a local ring R which we call the radius of X. We show that if R is a complete intersection and X is resolving, then finiteness of the radius forces X to…

Commutative Algebra · Mathematics 2016-01-20 Hailong Dao , Ryo Takahashi

We introduce higher-dimensional module factorizations associated to a regular sequence. They include higher-dimensional matrix factorizations, which are commutative cubes consisting of free modules with edges being classical matrix…

Rings and Algebras · Mathematics 2025-03-05 Xiao-Wu Chen

We give a combinatorial description of local cohomology modules of a graded module over a semigroup ring, with support at the graded maximal ideal. This combinatorial framework yields Hochster-type formulas for the Hilbert series of such…

Commutative Algebra · Mathematics 2022-11-22 Byeongsu Yu , Laura Felicia Matusevich

If $(A,\mathfrak{m})$ is a hypersurface ring of dimension $d$ with $e(A)=3$. Let $M$ be an MCM $A$-module with $\mu(M)=4$ then we prove that $\depth{G(M)}\geq d-3$.

Commutative Algebra · Mathematics 2023-03-03 Ankit Mishra , Tony J. Puthenpurakal

Let $(R,\fm)$ be commutative Noetherian local ring. It is shown that $R$ is Cohen--Macaulay ring if there exists a Cohen--Macaulay finite (i.e. finitely generated) $R$--module with finite upper Gorenstein dimension. In addition, we show…

Commutative Algebra · Mathematics 2007-05-23 Tirdad Sharif , Siamak Yassemi

Even if a ring A is coherent, the polynomial ring A[X] in one variable could fail to be coherent. In this note we show that A[X] is graded coherent with the standard grading deg X=1. More generally, we give a criterion of graded…

Rings and Algebras · Mathematics 2012-10-22 Hiroyuki Minamoto

Let $A = K[[X_1,\cdots,X_n]]$ and let $\mathfrak{m} = (X_1,\cdots,X_n)$. Let $M$ be a Cohen-Macaulay $A$-module of codimension $p$. In this paper we give a necessary and sufficient condition for the associated graded module…

Commutative Algebra · Mathematics 2014-09-08 Tony J. Puthenpurakal

Let $A=Q/(f)$ where $(Q,\mathfrak{n})$ be a complete regular local ring of dimension $d+1$, $f\in \mathfrak{n}^i\setminus\mathfrak{n}^{i+1}$ for some $i\geq 2$ and $M$ an MCM $A-$module with $e(M)=\mu(M)i(M)+1$ then we prove that depth…

Commutative Algebra · Mathematics 2022-08-05 Ankit Mishra , Tony J. Puthenpurakal

In this paper we are concerned with the following question: if the tensor product of finitely generated modules $M$ and $N$ over a local complete intersection domain is maximal Cohen-Macaulay, then must $M$ or $N$ be a maximal…

Commutative Algebra · Mathematics 2020-08-18 Olgur Celikbas , Arash Sadeghi

Let (R, m) be the semigroup ring associated to a numerical semigroup S. In this paper we study the property of its associated graded ring G(m) to be Complete Intersection. In particular, we introduce and characterise beta-rectangular and…

Commutative Algebra · Mathematics 2013-01-24 Marco D'Anna , Vincenzo Micale , Alessio Sammartano

Let $(A,\mathfrak{m})$ be a hypersurface ring with dimension $d$, and $M$ a MCM $A-$module with red$(M)\leq 2$ and $\mu(M)=2$ or $3$ then we have proved that depth $G(M)\geq d-\mu(M)+1$. If $e(A)=3$ and $\mu(M)=4$ then in this case we have…

Commutative Algebra · Mathematics 2022-03-15 Ankit Mishra , Tony J. Puthenpurakal

Let $R$ be an algebra essentially of finite type over a field $k$ and let $\Omega_k(R)$ be its module of K\"ahler differentials over $k$. If $R$ is a homogeneous complete intersection and $\mathrm{char}(k)=0$, we prove that $\Omega_k(R)$ is…

Commutative Algebra · Mathematics 2020-08-03 Alessandra Costantini , Tan Dang

Every quotient R/I of a semigroup ring R by a radical monomial ideal I has a unique minimal injective-like resolution by direct sums of quotients of R modulo prime monomial ideals. The quotient R/I is Cohen-Macaulay if and only if every…

Commutative Algebra · Mathematics 2007-05-23 Ezra Miller
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