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Suppose $f\in L^1(\mathbb{R}^d)$, $\Lambda\subset\mathbb{R}^d$ is a finite union of translated lattices such that $f+\Lambda$ tiles with a weight. We prove that there exists a lattice $L\subset{\mathbb{R}}^d$ such that $f+L$ also tiles,…

Combinatorics · Mathematics 2019-10-23 Bochen Liu

The $k$-tiling problem for a convex polytope $P$ is the problem of covering $\mathbb R^d$ with translates of $P$ using a discrete multiset $\Lambda$ of translation vectors, such that every point in $\mathbb R^d$ is covered exactly $k$…

Metric Geometry · Mathematics 2016-01-25 Swee Hong Chan

We study the problem of covering R^d by overlapping translates of a convex body P, such that almost every point of R^d is covered exactly k times. Such a covering of Euclidean space by translations is called a k-tiling. The investigation of…

Combinatorics · Mathematics 2011-03-17 Nick Gravin , Sinai Robins , Dmitry Shiryaev

When $\mathbb{Z}^d$ is represented as a finite disjoint union of translated integer sublattices, the translated sublattices must possess some special properties. Such a representation is called a \emph{lattice tiling}. We develop a…

Number Theory · Mathematics 2016-05-31 Maciej Borodzik , Danny Nguyen , Sinai Robins

We study multiple tilings of 3-dimensional Euclidean space by a convex body. In a multiple tiling, a convex body $P$ is translated with a discrete multiset $\Lambda$ in such a way that each point of the space gets covered exactly $k$ times,…

Combinatorics · Mathematics 2012-08-09 Nick Gravin , Mihail Kolountzakis , Sinai Robins , Dmitry Shiryaev

All simple translation-invariant valuations on polytopes are classified. As a direct consequence the well-known conditions for translative-equidecomposability are recovered. Furthermore, a simplified proof of the classification of…

Metric Geometry · Mathematics 2015-07-07 Katharina Kusejko , Lukas Parapatits

This paper shows that a multiple translative tile in the plane must be a multiple lattice tile.

Metric Geometry · Mathematics 2019-10-01 Qi Yang

We consider polygons with the following ``pairing property'': for each edge of the polygon there is precisely one other edge parallel to it. We study the problem of when such a polygon $K$ tiles the plane multiply when translated at the…

Metric Geometry · Mathematics 2007-05-23 Mihail N. Kolountzakis

In this paper, we prove that it is undecidable whether a set of two polycubes can tile $\mathbb{Z}^3$ by translation. The proof involves a new technique that allows us to simulate two disconnected polycubes with two connected polycubes. By…

Combinatorics · Mathematics 2025-08-19 Yoonhu Kim

Generalizing results by Valette, Zamfirescu and Laczkovich, we will prove that a convex body $K$ is a polytope if there are sufficiently many tilings which contain a tile similar to $K$. Furthermore, we give an example that this can not be…

Metric Geometry · Mathematics 2011-05-17 Karim Adiprasito

This paper proves the following statement: {\it If a convex body can form a twofold translative tiling in $\mathbb{E}^3$, it must be a parallelohedron.} In other words, it must be a parallelotope, a hexagonal prism, a rhombic dodecahedron,…

Metric Geometry · Mathematics 2021-06-30 Mei Han , Qi Yang , Kirati Sriamorn , Chuanming Zong

This paper proves the following results: Besides parallelograms and centrally symmetric hexagons, there is no other convex domain which can form a two-, three- or four-fold lattice tiling in the Euclidean plane. If a centrally symmetric…

Metric Geometry · Mathematics 2019-11-13 Qi Yang , Chuanming Zong

This paper proves the following statement: If a convex body can form a fivefold translative tiling in $\mathbb{E}^3$, it must be a parallelotope, a hexagonal prism, a rhombic dodecahedron, an elongated dodecahedron, a truncated octahedron,…

Metric Geometry · Mathematics 2023-10-31 Mei Han , Kirati Sriamorn , Qi Yang , Chuanming Zong

Suppose L and M are full-rank lattices in Euclidean space, such that vol(L) < vol(M). Answering a question of Han and Wang from 2001, we show how to construct a bounded measurable set F (we can even take F to be a finite union of polytopes)…

Classical Analysis and ODEs · Mathematics 2025-09-25 Sigrid Grepstad , Mihail N. Kolountzakis , Emmanuil Spyridakis

A biconvex polytope is a classical and tropical convex hull of finitely many points. Given a biconvex polytope, for each vertex of it we construct a directed bigraph and a gammoid so that the collection of base polytopes of those gammoids…

Algebraic Geometry · Mathematics 2022-12-21 Jaeho Shin

Our earlier article proved that if $n > 1$ translates of sublattices of $Z^d$ tile $Z^d$, and all the sublattices are Cartesian products of arithmetic progressions, then two of the tiles must be translates of each other. We re-prove this…

Combinatorics · Mathematics 2010-06-04 David Feldman , James Propp , Sinai Robins

A planar set $P$ is said to be cover-decomposable if there is a constant $k=k(P)$ such that every $k$-fold covering of the plane with translates of $P$ can be decomposed into two coverings. It is known that open convex polygons are…

Metric Geometry · Mathematics 2014-03-12 István Kovács , Géza Tóth

A lattice polytope translated by a rational vector is called an almost integral polytope. In this paper we investigate Ehrhart quasi-polynomials of almost integral polytopes. We study the relationship between the shape of the polytopes and…

Combinatorics · Mathematics 2023-08-31 Christopher de Vries , Masahiko Yoshinaga

We show that if two lattice $3$-polytopes $P$ and $P'$ have the same Ehrhart function then they are $\operatorname{GL}_3({\mathbb Z})$-equidecomposable; that is, they can be partitioned into relatively open simplices $U_1,\dots, U_k$ and…

Combinatorics · Mathematics 2019-12-17 Jakob Erbe , Christian Haase , Francisco Santos

Which polygons admit two (or more) distinct lattice tilings of the plane? We call such polygons double tiles. It is well-known that a lattice tiling is always combinatorially isomorphic either to a grid of squares or to a grid of regular…

Combinatorics · Mathematics 2025-02-24 Nikolai Beluhov
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