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In this paper, we study the existence of high-dimensional, closed, smooth manifolds whose rational homotopy type resembles that of a projective plane. Applying rational surgery, the problem can be reduced to finding possible Pontryagin…

Geometric Topology · Mathematics 2016-01-20 Zhixu Su

Let $\Bbbk$ be a field of characteristic zero and $G$ be a finite group of automorphisms of projective plane over $\Bbbk$. Castelnuovo's criterion implies that the quotient of projective plane by $G$ is rational if the field $\Bbbk$ is…

Algebraic Geometry · Mathematics 2013-01-24 Andrey S. Trepalin

We show by finding an explicit parametrization that a 4th degree surface which arises as a necessary condition for the existence of a perfect cuboid is a rational surface, i.e. birationally equivalent over $\mathbb Q$ to a plane.

Number Theory · Mathematics 2012-07-24 John R. Ramsden

We study real double covers of $\mathbb P^1\times\mathbb P^2$ branched over a $(2,2)$-divisor, which have the structure of a conic bundle threefold with smooth quartic discriminant curve via the second projection. In each isotopy class of…

Algebraic Geometry · Mathematics 2023-03-22 Lena Ji , Mattie Ji

In the open problem of classification of rational cuspidal plane curves it is essential to find good necessary conditions on the type of singularities of a curve C in order C to exit. Motivated by the study of the Seiberg-Witten invariant…

Algebraic Geometry · Mathematics 2007-05-23 J. Fernández de Bobadilla , I. Luengo-Velasco , A. Melle-Hernández , A. Némethi

Let $C$ be an irreducible projective plane curve in the complex projective space ${\mathbb{P}}^2$. The classification of such curves, up to the action of the automorphism group $PGL(3,{\mathbb{C}})$ on ${\mathbb{P}}^2$, is a very difficult…

Algebraic Geometry · Mathematics 2007-05-23 J. Fernandez de Bobadilla , I. Luengo , A. Melle-Hernandez , A. Nemethi

The Hirzebruch signature formula provides an obstruction to the following realization question: given a rational Poincar\'e duality algebra $\mathcal{A}$, does there exist a smooth manifold $M$ such that $H^*(M;\mathbb{Q})=\mathcal{A}$?…

Geometric Topology · Mathematics 2014-03-10 Jim Fowler , Zhixu Su

Let X be a non-singular projective hypersurface of degree 4, which is defined over the rational numbers. Assume that X has dimension 39 or more, and that X contains a real point and p-adic points for every prime p. Then X is shown to…

Number Theory · Mathematics 2008-01-08 T. D. Browning , D. R. Heath-Brown

Let $X \subset \mathbb{P}(w_0, w_1, w_2, w_3)$ be a quasismooth well-formed weighted projective hypersurface and let $L = lcm(w_0,w_1,w_2,w_3)$. We characterize when $X$ is rational under the assumption that $L$ divides $deg(X)$ by…

Algebraic Geometry · Mathematics 2024-01-25 Michael Chitayat

A Q-homology plane is a normal complex algebraic surface having trivial rational homology. We obtain a structure theorem for Q-homology planes with smooth locus of non-general type. We show that if a Q-homology plane contains a non-quotient…

Algebraic Geometry · Mathematics 2014-02-21 Karol Palka

We implement two-cover descent for plane quartics over Q with all 28 bitangents rational and show that on a significant collection of test cases, it resolves the existence of rational points. We also review a classical description of the…

Number Theory · Mathematics 2023-06-05 Nils Bruin , Daniel Lewis

For any positive integer $r$, we construct a smooth complex projective rational surface which has at least $r$ real forms not isomorphic over $\mathbb{R}$.

Algebraic Geometry · Mathematics 2022-02-11 Anna Bot

We prove the projective plane $\rp^2$ is an absolute extensor of a finite-dimensional metric space $X$ if and only if the cohomological dimension mod 2 of $X$ does not exceed 1. This solves one of the remaining difficult problems (posed by…

Geometric Topology · Mathematics 2014-10-01 Jerzy Dydak , Michael Levin

We show that any smooth lattice polytope P with codegree greater or equal than (dim(P)+3)/2 (or equivalently, with degree smaller than dim(P)/2), defines a dual defective projective toric manifold. This implies that P is Q-normal (in the…

Combinatorics · Mathematics 2010-01-19 Alicia Dickenstein , Benjamin Nill

From a topological viewpoint, a rational curve in the real projective plane is generically a smoothly immersed circle and a finite collection of isolated points. We give an isotopy classification of generic rational quintics in…

Algebraic Geometry · Mathematics 2019-10-14 Ilia Itenberg , Grigory Mikhalkin , Johannes Rau

Given two rational, properly parametrized space curves ${\mathcal C}_1$ and ${\mathcal C}_2$, where $\CCC_2$ is contained in some plane $\Pi$, we provide an algorithm to check whether or not there exist perspective or parallel projections…

Algebraic Geometry · Mathematics 2016-03-25 Juan Gerardo Alcázar , Carlos Hermoso

This article addresses the existence of $\Q$-rational periodic points for morphisms of projective space. In particular, we construct an infinitely family of morphisms on $\P^N$ where each component is a degree 2 homogeneous form in $N+1$…

Dynamical Systems · Mathematics 2009-08-04 Benjamin Hutz

These results stem from a course on ring theory. Quantum planes are rings in two variables $x$ and $y$ such that $yx=qxy$ where $q$ is a nonzero constant. When $q=1$ a quantum plane is simply a commutative polynomial ring in two variables.…

Rings and Algebras · Mathematics 2007-05-23 Romain Coulibaly , Kenneth price

Let $k$ be a field with char $k \not= 2$, $X$ be an affine surface defined by the equation $z^2=P(x)y^2+Q(x)$ where $P(x), Q(x) \in k[x]$ are separable polynomials. We will investigate the rationality problem of $X$ in terms of the…

Algebraic Geometry · Mathematics 2015-09-22 Aiichi Yamasaki

We consider the problem of computing a triangulation of the real projective plane P2, given a finite point set S={p1, p2,..., pn} as input. We prove that a triangulation of P2 always exists if at least six points in S are in general…

Computational Geometry · Computer Science 2011-11-10 Mridul Aanjaneya , Monique Teillaud
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