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Related papers: Indecomposable $1$-factorizations of the complete …

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For a given graph $R$, a graph $G$ is $R$-free if $G$ does not contain $R$ as an induced subgraph. It is known that every $2$-tough graph with at least three vertices has a $2$-factor. In graphs with restricted structures, it was shown that…

Combinatorics · Mathematics 2022-04-08 Elizabeth Grimm , Songling Shan , Anna Johnsen

We establish by means of a computer search that a complete graph on 14 vertices has 98,758,655,816,833,727,741,338,583,040 distinct and 1,132,835,421,602,062,347 nonisomorphic one-factorizations. The enumeration is constructive for the…

Combinatorics · Mathematics 2008-01-03 Petteri Kaski , Patric R. J. Östergård

A graph is equimatchable if each of its matchings is a subset of a maximum matching. It is known that any 2-connected equimatchable graph is either bipartite, or factor-critical, and that these two classes are disjoint. This paper provides…

Combinatorics · Mathematics 2015-01-30 Eduard Eiben , Michal Kotrbcik

An irreducible element of a commutative ring is absolutely irreducible if no power of it has more than one (essentially different) factorization into irreducibles. In the case of the ring $\text{Int}(D)=\{f\in K[x]\mid f(D)\subseteq D\}$,…

Commutative Algebra · Mathematics 2020-04-02 Sophie Frisch , Sarah Nakato

Let $f_r(n)$ be the minimum number of complete $r$-partite $r$-graphs needed to partition the edge set of the complete $r$-uniform hypergraph on $n$ vertices. Graham and Pollak showed that $f_2(n) = n-1$. An easy construction shows that…

Combinatorics · Mathematics 2017-01-31 Imre Leader , Luka Milićević , Ta Sheng Tan

We prove that every 0/1-polytope has a unique Minkowski decomposition into indecomposable polytopes, up to translation of summands. The summands lie in pairwise orthogonal subspaces. Thus, every 0/1-polytope is the Cartesian product of…

Combinatorics · Mathematics 2026-05-22 Akihiro Higashitani , Arnau Padrol , Raman Sanyal

Let $\mathcal{H}=\{H_i: i<\alpha \}$ be an indexed family of graphs for some ordinal number $\alpha$. $\mathcal{H}$-decomposition of a graph $G$ is a family $\mathcal{G}=\{G_i: i<\alpha \}$ of edge-disjoint subgraphs of $G$ such that $G_i$…

Combinatorics · Mathematics 2021-07-20 Marcin Stawiski

It is a challenging open problem to construct an explicit 1-factorization of the bipartite Kneser graph $H(v,t)$, which contains as vertices all $t$-element and $(v-t)$-element subsets of $[v]:=\{1,\ldots,v\}$ and an edge between any two…

Discrete Mathematics · Computer Science 2019-04-04 Kai Jin

A square (0,1)-matrix X of order n > 0 is called fully indecomposable if there exists no integer k with 0 < k < n, such that X has a k by n-k zero submatrix. A stable set of a graph G is a subset of pairwise nonadjacent vertices. The…

Combinatorics · Mathematics 2007-05-23 Vadim E. Levit , Eugen Mandrescu

In this note, we prove that every even regular multigraph on $n$ vertices with multiplicity at most $r$ and minimum degree at least $rn/2 + o(n)$ has a Hamilton decomposition. This generalises a result of Vaughan who proved an asymptotic…

Combinatorics · Mathematics 2023-12-18 Vincent Pfenninger

A graph of order $n$ is said to be $k$-\emph{factor-critical} $(0\le k<n)$ if the removal of any $k$ vertices results in a graph with a perfect matching. A $k$-factor-critical graph $G$ is \emph{minimal} if $G-e$ is not $k$-factor-critical…

Combinatorics · Mathematics 2026-03-12 Kevin Pereyra

Let $k\geq\ell\geq1$ and $n\geq 1$ be integers. Let $G(k,n)$ be the complete $k$-partite graph with $n$ vertices in each colour class. An $\ell$-decomposition of $G(k,n)$ is a set $X$ of copies of $K_k$ in $G(k,n)$ such that each copy of…

Combinatorics · Mathematics 2012-02-20 Ruy Fabila-Monroy , David R. Wood

A tree containing exactly two non-pendant vertices is called a double-star. Let $k_1$ and $k_2$ be two positive integers. The double-star with degree sequence $(k_1+1, k_2+1, 1, \ldots, 1)$ is denoted by $S_{k_1, k_2}$. If $G$ is a cubic…

Combinatorics · Mathematics 2015-09-11 Saieed Akbari , Hamidreza Maimani , Abbas Seify

A spanning subgraph of a graph G is called a [0,2]-factor of G, if for . is a union of some disjoint cycles, paths and isolate vertices, that span the graph G. It is easy to get a [0,2]-factor of G and there would be many of [0,2]-factors…

Combinatorics · Mathematics 2011-11-03 Yingtai Xie

We enumerate factorisations of the complete graph into spanning regular graphs in several cases, including when the degrees of all the factors except for one or two are small. The resulting asymptotic behaviour is seen to generalise the…

Combinatorics · Mathematics 2022-06-28 Mahdieh Hasheminezhad , Brendan D. McKay

In this paper, we explore the concept of the ``matrix product of graphs," initially introduced by Prasad, Sudhakara, Sujatha, and M. Vinay. This operation involves the multiplication of adjacency matrices of two graphs with assigned labels,…

Combinatorics · Mathematics 2023-12-15 Farzad Maghsoudi , Babak Miraftab , Sho Suda

Let $G$ be a graph with vertex set $V(G)$. Let $n$ and $k$ be non-negative integers such that $n + 2k \leq |V(G)| - 2$ and $|V(G)| - n$ is even. If when deleting any $n$ vertices of $G$ the remaining subgraph contains a matching of $k$…

Combinatorics · Mathematics 2007-05-23 Guizhen Liu , Qinglin Yu

We show that for all graphs H of size n, the complete graph $K_{2n+1}$ has an $H$-decomposition.

Discrete Mathematics · Computer Science 2010-08-02 Jesse Gilbert

We determine all factorisations $X=AB$, where $X$ is a finite almost simple group and $A,B$ are core-free subgroups such that $A\cap B$ is cyclic or dihedral. As a main application, we classify the graphs $\Gamma$ admitting an almost simple…

Group Theory · Mathematics 2024-05-24 Martin W. Liebeck , Cheryl E. Praeger

By utilizing the recently developed hypergraph analogue of Godsil's identity by the second author, we prove that for all $n \geq k \geq 2$, one can reconstruct the matching polynomial of an $n$-vertex $k$-uniform hypergraph from the…

Combinatorics · Mathematics 2025-02-03 Donggyu Kim , Hyunwoo Lee