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An irredundant cover of a finite group $G$ is a collection of proper subgroups whose union is $G$ and which contains no smaller subcover. We classify finite groups which possess exactly two irredundant covers, thereby initiating an answer…

Group Theory · Mathematics 2022-06-22 Jonathan Cohen , Kyle Rosengartner

There are various results in the literature which are part of the general philosophy that a finite group for which a certain parameter (for example, the number of conjugacy classes or the maximum number of elements inverted, squared or…

Group Theory · Mathematics 2016-06-03 Alexander Bors

The paper discusses the Andrews-Curtis graph of a normal subgroup N in a group G. The vertices of the graph are k-tuples of elements in N which generate N as a normal subgroup; two vertices are connected if one them can be obtained from…

Group Theory · Mathematics 2007-05-23 Alexandre V. Borovik , Evgenii I. Khukhro , Alexei G. Myasnikov

A slice (G, S) of finite groups is a pair consisting of a finite group G and a subgroup S of G. In this paper, we show that some properties of finite groups extend to slices of finite groups. In particular, by analogy with B-groups, we…

Group Theory · Mathematics 2021-09-28 Ibrahima Tounkara

The knots-quivers correspondence states that various characteristics of a knot are encoded in the corresponding quiver and the moduli space of its representations. However, this correspondence is not a bijection: more than one quiver may be…

High Energy Physics - Theory · Physics 2021-10-20 Jakub Jankowski , Piotr Kucharski , Hélder Larraguível , Dmitry Noshchenko , Piotr Sułkowski

Let $G$ be a finite group. We prove a theorem implying that the orders of elements of the holomorph $\operatorname{Hol}(G)$ are bounded from above by $|G|$, and we discuss an application to bounding automorphism orders of finite groups.

Group Theory · Mathematics 2015-10-08 Alexander Bors

To any finite group $G$, we may associate a graph whose vertices are the elements of $G$ and where two distinct vertices $x$ and $y$ are adjacent if and only if the order of the subgroup $\langle x, y\rangle$ is divisible by at least 3…

Group Theory · Mathematics 2023-09-12 Karmele Garatea-Zaballa , Andrea Lucchini

We say that finite groups are isospectral if they have the same sets of orders of elements. It is known that every nonsolvable finite group $G$ isospectral to a finite simple group has a unique nonabelian composition factor, that is, the…

Group Theory · Mathematics 2022-07-07 Maria A. Grechkoseeva , Andrey V. Vasil'ev

For every genus $g\geq 2$, we construct an infinite family of strongly quasipositive fibred knots having the same Seifert form as the torus knot $T(2,2g+1)$. In particular, their signatures and four-genera are maximal and their homological…

Geometric Topology · Mathematics 2021-05-27 Filip Misev

We describe an efficient algorithm to write any element of the alternating group A_n as a product of two n-cycles (in particular, we show that any element of A_n can be so written -- a result of E. A. Bertram). An easy corollary is that…

Group Theory · Mathematics 2007-05-23 Henry Cejtin , Igor Rivin

Two finitely generated groups have the same set of finite quotients if and only if their profinite completions are isomorphic. Consider the map which sends (the isomorphism class of) an S-arithmetic group to (the isomorphism class of) its…

Group Theory · Mathematics 2011-10-25 Menny Aka

A powerful way to study groups is via their actions on suitable spaces. Classifying spaces for families of subgroups are a type of these spaces, obtained by imposing some strict conditions on the fixed-point sets. We show how in the…

Algebraic Topology · Mathematics 2016-11-11 Federico William Pasini

Let $G$ be a finite group admitting a coprime automorphism $\alpha$ of order $e$. Denote by $I_G(\alpha)$ the set of commutators $g^{-1}g^\alpha$, where $g\in G$, and by $[G,\alpha]$ the subgroup generated by $I_G(\alpha)$. We study the…

Group Theory · Mathematics 2022-03-28 Cristina Acciarri , Robert M. Guralnick , Pavel Shumyatsky

Let $K$ be field of characteristic 2 and let $G$ be a finite non-abelian 2-group with the cyclic derived subgroup $G'$, and there exists a central element $z$ of order 2 in $Z(G) \backslash G'$. We prove that the unit group of the group…

Rings and Algebras · Mathematics 2008-01-03 Alexander Konovalov

Let $G$ be a finite group. Denote by $\textrm{Irr}(G)$ the set of all irreducible complex characters of $G.$ Let $\textrm{cd}(G)=\{\chi(1)\;|\;\chi\in \textrm{Irr}(G)\}$ be the set of all irreducible complex character degrees of $G$…

Group Theory · Mathematics 2011-02-23 Hung P. Tong-Viet

We show that certain factor rings of the group algebra of a symmetric group have natural bases of group elements. We also give generators for the annihilator of certain permutation modules for symmetric groups.

Representation Theory · Mathematics 2024-12-03 Stephen Donkin

The non-solvable graph of a finite group G is a simple graph whose vertices are the elements of G and there is an edge between x and y if and only if the subgroup generated by x and y is not solvable. The isolated vertices in the…

Group Theory · Mathematics 2018-06-05 B. Akbari

Let $G$ be a group. The power graph of $G$ is a graph with vertex set $G$ in which two distinct elements $x,y$ are adjacent if one of them is a power of the other. We characterize all groups whose power graphs have finite independence…

Combinatorics · Mathematics 2019-10-16 P. J. Cameron , S. H. Jafari

A group is boundedly simple if, for some constant N, every nontrivial conjugacy class generates the whole group in N steps. For a large class of trees, Tits proved simplicity of a canonical subgroup of the automorphism group, which is…

Group Theory · Mathematics 2012-06-29 Jakub Gismatullin

Let G and F be finitely generated groups with infinitely many ends and let A and B be graph of groups decompositions of F and G such that all edge groups are finite and all vertex groups have at most one end. We show that G and F are…

Geometric Topology · Mathematics 2007-05-23 Panos Papazoglu , Kevin Whyte