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Related papers: Remarks on strictly singular operators

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A bounded linear operator between Banach spaces is called {\it completely continuous} if it carries weakly convergent sequences into norm convergent sequences. Isolated is a universal operator for the class of non-completely-continuous…

Functional Analysis · Mathematics 2016-09-06 Maria Girardi , William B. Johnson

We characterize the limited operators by differentiability of convex continuous functions. Given Banach spaces $Y$ and $X$ and a linear continuous operator $T: Y \longrightarrow X$, we prove that $T$ is a limited operator if and only if,…

Functional Analysis · Mathematics 2016-02-15 Mohammed Bachir

We prove that if T is a strictly singular 1-1 operator defined on an infinite dimensional Banach space X, then for every infinite dimensional subspace Y of X there exists an infinite dimensional subspace Z of Y such that Z contains orbits…

Functional Analysis · Mathematics 2007-05-23 George Androulakis , Per Enflo

The question whether an operator belongs to the domain of some singular trace is addressed, together with the dual question whether an operator does not belong to the domain of some singular trace. We show that the answers are positive in…

Operator Algebras · Mathematics 2007-05-23 Daniele Guido , Tommaso Isola

Let $T$ be an absolutely continuous polynomially bounded operator, and let $\theta$ be a singular inner function. It is shown that if $\theta(T)$ is invertible and some additional conditions are fulfilled, then $T$ has nontrivial…

Functional Analysis · Mathematics 2019-12-17 Maria F. Gamal'

An operator $T $ from a vector lattice $E$ into a normed lattice $F$ is called unbounded $\sigma$-order-to-norm continuous whenever $x_{n}\xrightarrow{uo}0$ implies $\| Tx_{n}\|\rightarrow 0$, for each sequence $(x_{n})_n\subseteq E$. For a…

Functional Analysis · Mathematics 2019-08-09 Mina Matin , Kazem Haghnejad Azar , Razi Alavizadeh

A continuous linear operator L defined on the space of entire functions H(C) is said to be an extended $lambda$-eigenoperator of the differentiation operator D provided DL = $lambda$LD. Here we fully characterize when an extended…

Functional Analysis · Mathematics 2022-07-28 Manuel González , Fernando León-Saavedra , María Pilar Romero de la Rosa

For locally convex spaces $X$ and $Y$, the continuous linear map $T:X \to Y$ is called bounded if there is a zero neighborhood $U$ of $X$ such that $T(U)$ is bounded in $Y$. Our main result is that the existence of an unbounded operator $T$…

Functional Analysis · Mathematics 2018-08-20 Ersin Kızgut , Murat Yurdakul

We explore the relation between lattice versions of strict singularity for operators from a Banach lattice to a Banach space. In particular, we study when the class of disjointly strictly singular operators, those not invertible on the span…

Functional Analysis · Mathematics 2014-10-20 Julio Flores , Jordi López-Abad , Pedro Tradacete

Let $E$ and $G$ be two Banach function spaces, let $T \in \mathcal{L}(E,Y)$, and let ${\langle X,Y \rangle}$ be a Banach dual pair. In this paper we give conditions for which there exists a (necessarily unique) bounded linear operator…

Functional Analysis · Mathematics 2015-10-20 Nick Lindemulder

Exploiting several $\ell_p$-factorization results for strictly singular operators, we study the strict singularity of the multiplication operator $L_A R_B\colon T\mapsto ATB$ on $\mathcal L(X)$ for various Banach spaces~$X$.

Functional Analysis · Mathematics 2019-05-15 Martin Mathieu , Pedro Tradacete

For Fr{\'e}chet spaces E and F we write (E,F) \in {B} if every continuous linear operator from E to F is bounded. Let l be a Banach sequence space with a monotone norm in which the canonical system (e_{n}) is an unconditional basis. We…

Functional Analysis · Mathematics 2017-04-17 Elif Uyanık , Murat H. Yurdakul

We investigate possible quantifications of strictly singular operators, $l_{p}$-strictly singular operators, $c_{0}$-strictly singular operators, strictly cosingular operators, $l_{p}$-strictly cosingular operators. We prove quantitative,…

Functional Analysis · Mathematics 2016-08-29 Lei Li , Dongyang Chen

Let $X$ be a vector lattice and $(E,\tau)$ be a locally solid vector lattice. An operator $T:X\to E$ is said to be $ob$-bounded if, for each order bounded set $B$ in $X$, $T(B)$ is topologically bounded in $E$. In this paper, we study on…

Functional Analysis · Mathematics 2018-02-12 Abdullah Aydın

Given a continuous real-valued function on [0, 1], and a closed subset E \subset [0, 1] we denote by f E the restriction of f to E, that is, the function defined only on E that takes the same values as f at every point of E >. The…

Classical Analysis and ODEs · Mathematics 2007-11-29 Jean-Pierre Kahane , Yitzhak Katznelson

For each $n \in \mathbb{N}$ a Banach space $\mathfrak{X}_{0,1}^n$ is constructed is having the property that every normalized weakly null sequence generates either a $c_0$ or $\ell_1$ spreading models and every infinite dimensional subspace…

Functional Analysis · Mathematics 2013-09-19 Spiros Argyros , Kevin Beanland , Pavlos Motakis

In this paper we introduce two new classes of operators that we call strongly order continuous and strongly $\sigma$-order continuous operators. An operator $T:E\rightarrow F$ between two Riesz spaces is said to be strongly order continuous…

Functional Analysis · Mathematics 2017-12-13 Akbar Bahramnezhad , Kazem Haghnejad Azar

For every closed subset $X$ of a stratifiable [resp. metrizable] space $Y$ we construct a positive linear extension operator $T:R^{X\times X}\to R^{Y\times Y}$ preserving constant functions, bounded functions, continuous functions,…

General Topology · Mathematics 2012-02-08 Taras Banakh , Czeslaw Bessaga

An algebra A of operators on a Banach space X is called strictly semi-transitive if for all non-zero x,y in X there exists an operator S in A such that Sx=y or Sy=x. We show that if A is norm-closed and strictly semi-transitive, then every…

Functional Analysis · Mathematics 2007-05-23 H. P. Rosenthal , V. G. Troitsky

Let $H_1,H_2$ be complex Hilbert spaces and $T$ be a densely defined closed linear operator (not necessarily bounded). It is proved that for each $\epsilon>0$, there exists a bounded operator $S$ with $\|S\|\leq \epsilon$ such that $T+S$ is…

Functional Analysis · Mathematics 2016-09-23 S. H. Kulkarni , G. Ramesh
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