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$(1)$ Let $M\subset N$ be a commutative cancellative torsion-free and subintegral extension of monoids. Then we prove that in the case of ring extension $A[M]\subset A[N]$, the two notions, subintegral and weakly subintegral coincide…

Commutative Algebra · Mathematics 2025-07-21 Md Abu Raihan , Leslie G. Roberts , Husney Parvez Sarwar

Let $A\subset B$ be an integral ring extension of integral domains with fields of fractions $K$ and $L$, respectively. The integral degree of $A\subset B$, denoted by ${\rm d}_A(B)$, is defined as the supremum of the degrees of minimal…

Commutative Algebra · Mathematics 2018-03-02 José M. Giral , Liam O'Carroll , Francesc Planas-Vilanova , Bernat Plans

If $i:A\subset B$ is a commutative ring extension, we show that the group $\mathcal I(A,B)$ of invertible $A$-submodules of $B$ is contracted in the sense of Bass, with $L\mathcal I(A,B)=H^0_{et}(A,i_*\mathbb Z/\mathbb Z)$. This gives a…

Commutative Algebra · Mathematics 2016-06-14 Vivek Sadhu , Charles Weibel

Let $A\subset B$ be an extension of commutative reduced rings and $M\subset N$ an extension of positive commutative cancellative torsion-free monoids. We prove that $A$ is subintegrally closed in $B$ and $M$ is subintegrally closed in $N$…

Commutative Algebra · Mathematics 2015-05-21 Husney Parvez Sarwar

A subring pair B < A has right depth 2n if the n+1'st relative Hochschild bar resolution group is isomorphic to a direct summand of a multiple of the n'th relative Hochschild bar resolution group as A-B-bimodules; depth 2n+1 if the same…

Rings and Algebras · Mathematics 2012-06-27 Lars Kadison

Let $M$ be a left module over a ring $R$ and $I$ an ideal of $R$. $M$ is called an $I$-supplemented module (finitely $I$-supplemented module) if for every submodule (finitely generated submodule) $X$ of $M$, there is a submodule $Y$ of $M$…

Rings and Algebras · Mathematics 2011-08-18 Yongduo Wang

Let $\mathfrak{a}$ be an ideal of a commutative noetherian ring $R$, $\mathcal{S}$ a Serre subcategory of $R$-modules satisfying the condition $C_\mathfrak{a}$ and $\mathcal{N}$ the subcategory of finitely generated $R$-modules. In this…

Commutative Algebra · Mathematics 2022-09-14 Xiaoyan Yang

We give necessary and sufficient conditions on an Ore extension $A[x;\sigma,\delta]$, where $A$ is a finite dimensional algebra over a field $\mathbb{F}$, for being a Frobenius extension over the ring of commutative polynomials…

In this paper our main theorem states the following, Main Theorem : Let B denote the polynomial ring D[x1,.... ,xn] , in the commuting indeterminates x i over a division ring D . Let M be a finitely generated B-module . Let B m denote the…

Rings and Algebras · Mathematics 2014-10-07 C. L. Wangneo

For any extension of commutative rings $A\subseteq B$, by using invertible ideals, we first define an Abelian group $\Cl(A,B)$, that we call the ideal class group of this extension. Then we study the main properties of this group. Among…

Commutative Algebra · Mathematics 2026-04-17 Abolfazl Tarizadeh

Let $A$ be a commutative noetherian ring, let $\mathfrak a$ be an ideal of $A$ and let $n$ be a non-negative integer. In this paper, we study $\mathcal{S}_{n}(\mathfrak{a})$, a certain class of $A$-modules and we find some sufficient…

Commutative Algebra · Mathematics 2023-02-09 Hajar Sabzeh , Reza Sazeedeh

Let $F$ be a finite set of monomials of the same degree $d\geq 2$ in a polynomial ring $R=k[x_1,...,x_n]$ over an arbitrary field $k$. We give some necessary and/or sufficient conditions for the birationality of the ring extension…

Commutative Algebra · Mathematics 2011-04-05 Aron Simis , Rafael H. Villarreal

$\textbf{Theorem 1.2.}$ For a ring $A$, the following conditions are equivalent. $\textbf{1)}$ $A$ is a right automorphism-invariant right non-singular ring. $\textbf{2)}$ $A$ is a right automorphism-invariant regular ring. $\textbf{3)}$…

Rings and Algebras · Mathematics 2017-04-20 Askar Tuganbaev

Let $R$ be a standard graded polynomial ring that is finitely generated over a field of characteristic $0$, let $\mathfrak{m}$ be the homogeneous maximal ideal of $R$, and let $I$ be a homogeneous prime ideal of $R$. Dao and Monta\~{n}o…

Commutative Algebra · Mathematics 2019-12-12 Jennifer Kenkel

In this paper we investigate extended modules for a special class of Ore extensions. We will assume that $R$ is a ring and $A$ will denote the Ore extension $A:=R[x_1,\dots,x_n;\sigma]$ for which $\sigma$ is an automorphism of $R$,…

Rings and Algebras · Mathematics 2015-03-09 Vyacheslav Artamonov , William Fajardo , Oswaldo Lezama

For an extension A/B of neither necessarily associative nor necessarily unital rings, we investigate the connection between simplicity of A with a property that we call A-simplicity of B. By this we mean that there is no non-trivial ideal I…

Rings and Algebras · Mathematics 2014-02-17 Patrik Nystedt , Johan Öinert

We say that a cover of surfaces S -> X has the Birman--Hilden property if the subgroup of the mapping class group of X consisting of mapping classes that have representatives that lift to S embeds in the mapping class group of S modulo the…

Geometric Topology · Mathematics 2013-09-17 Rebecca R. Winarski

We study from an algebraic point of view the question of extending an action of a group \(\Gamma\) on a commutative domain \(R\) to a formal pseudodifferential operator ring \(B=R(\!(x\,;\,d)\!)\) with coefficients in \(R\), as well as to…

Number Theory · Mathematics 2019-07-12 François Dumas , François Martin

Let C be a finite dimensional algebra with B a split extension by a nilpotent bimodule E, and let M be a ${\tau}$-rigid C-module with U its Bongartz ${\tau}$-complement. If the induced module, $M{\otimes_C}B$, is ${\tau}$-rigid as a…

Representation Theory · Mathematics 2019-10-16 Stephen Zito

Necessary and sufficient conditions are given for the completed group algebras of a compact p-adic analytic group with coefficient ring the p-adic integers or the field of p elements to be prime, semiprime and a domain. Necessary and…

Rings and Algebras · Mathematics 2007-05-23 Konstantin Ardakov , Kenneth A. Brown
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