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The stable Kauffman conjecture posits that a knot in $S^3$ is slice if and only if it admits a slice derivative. We prove a related statement: A knot is handle-ribbon (also called strongly homotopy-ribbon) in a homotopy 4-ball $B$ if and…

Geometric Topology · Mathematics 2020-05-25 Maggie Miller , Alexander Zupan

In [D.A. Fedoseev, V.O. Manturov, A sliceness criterion for odd free knots,arXiv:1707.04923], the authors proved a sliceness criterion for odd free knots: free knots with odd chords. In the present paper we give a similar criterion for…

Geometric Topology · Mathematics 2017-10-03 Denis Fedoseev , Vassily Manturov

A knotted ribbon is one of physical aspect of a knot. A folded ribbon knot is a depiction of a knot obtained by folding a long and thin rectangular strip to become flat. The ribbonlength of a knot type can be defined as the minimum length…

Geometric Topology · Mathematics 2026-02-25 Hyoungjun Kim , Sungjong No , Hyungkee Yoo

We present a short proof of a theorem of Tanaka that if a composite ribbon knot admits a symmetric union presentation with one twisting region, then it has a non-trivial knot and its mirror image as connected summands.

Geometric Topology · Mathematics 2021-03-25 Feride Ceren Kose

We construct ribbon surfaces of Euler characteristic one for several infinite families of alternating 3-braid closures. We also use a twisted Alexander polynomial obstruction to conclude the classification of smoothly slice knots which are…

Geometric Topology · Mathematics 2023-06-22 Vitalijs Brejevs

We give a necessary, and in some cases sufficient, condition for sliceness inside the family of pretzel knots $P (p_1,...,p_n)$ with one $p_i$ even. The three stranded case yields two interesting families of examples: the first consists of…

Geometric Topology · Mathematics 2016-01-20 Ana G. Lecuona

There are 352.2 million prime knots in the 3-sphere with at most 19 crossings. We study which of these knots are slice, in both the smooth and topological categories. While no algorithm is known for deciding whether a given knot is slice in…

Geometric Topology · Mathematics 2025-12-29 Nathan M. Dunfield , Sherry Gong

We use recently introduced Rasmussen invariant to find knots that are topologically locally-flatly slice but not smoothly slice. We note that this invariant can be used to give a combinatorial proof of the slice-Bennequin inequality.…

Geometric Topology · Mathematics 2018-06-19 Alexander N. Shumakovitch

A knot in $S^3$ is rationally slice if it bounds a disk in a rational homology ball. We give an infinite family of rationally slice knots that are linearly independent in the knot concordance group. In particular, our examples are all…

Geometric Topology · Mathematics 2023-02-01 Jennifer Hom , Sungkyung Kang , JungHwan Park , Matthew Stoffregen

It is known that the linking form on the 2-cover of slice knots has a metabolizer. We show that several weaker conditions, or some other conditions related to sliceness, do not imply the existence of a metabolizer. We then show how the…

Geometric Topology · Mathematics 2009-09-29 A. Stoimenow

In answer to a question of Long, Flapan constructed an example of a prime strongly positive amphicheiral knot that is not slice. Long had proved that all such knots are algebraically slice. Here we show that the concordance group of…

Geometric Topology · Mathematics 2014-10-01 Charles Livingston

The ribbonlength Rib$(K)$ of a knot $K$ is the infimum of the ratio of the length of any flat knotted ribbon with core $K$ to its width. A twisted torus knot $T_{p,q;r,s}$ is obtained from the torus knot $T_{p,q}$ by twisting $r$ adjacent…

Geometric Topology · Mathematics 2022-08-09 Hyoungjun Kim , Sungjong No , Hyungkee Yoo

An open question asks if every knot of 4-genus g_s can be changed into a slice knot by g_s crossing changes. A counterexample is given.

Geometric Topology · Mathematics 2014-10-01 Charles Livingston

In the 60's Levine proved that if $R$ is a slice knot, then on any genus $g$ Seifert surface for $R$ there is a $g$ component link $J$, called a derivative of $R$, on which the Seifert form vanishes. Many subsequent obstructions to $R$…

Geometric Topology · Mathematics 2016-06-14 Tim Cochran , Christopher William Davis

We take a close look at a classical magic trick performed with a string, where a trivial knot is seemingly isotoped into a trefoil, and generalize it to a family of magic tricks for transforming the unknot into other knots. We encode such a…

Geometric Topology · Mathematics 2026-04-16 Raphael Appenzeller , José Pedro Quintanilha

We prove that an odd pretzel knot is doubly slice if it has $2n+1$ twist parameters consisting of $n+1$ copies of $a$ and $n$ copies of $-a$ for some odd integer $a$. Combined with the work of Issa and McCoy, it follows that these are the…

Geometric Topology · Mathematics 2019-06-10 Clayton McDonald

Given a simply-connected 4-manifold with boundary the 3-sphere, this paper establishes sufficient conditions for a knot in the boundary to be sliced by a locally flat disc in the 4-manifold, whose complement has finite cyclic fundamental…

Geometric Topology · Mathematics 2025-07-02 Anthony Conway , Patrick Orson , Mark Pencovitch

We study the relationship between fibered ribbon 1-knots and fibered ribbon 2-knots by studying fibered slice disks with handlebody fibers. We give a characterization of fibered homotopy-ribbon disks and give analogues of the Stallings…

Geometric Topology · Mathematics 2017-08-08 Kyle Larson , Jeffrey Meier

For $\ell >1$, we develop $L^{(2)}$-signature obstructions for $(4\ell-3)$-dimensional knots with metabelian knot groups to be doubly slice. For each $\ell>1$, we construct an infinite family of knots on which our obstructions are non-zero,…

Geometric Topology · Mathematics 2019-09-19 Patrick Orson , Mark Powell

A knot in $S^3$ is topologically slice if it bounds a locally flat disk in $B^4$. A knot in $S^3$ is rationally slice if it bounds a smooth disk in a rational homology ball. We prove that the smooth concordance group of topologically and…

Geometric Topology · Mathematics 2023-04-14 Jennifer Hom , Sungkyung Kang , JungHwan Park