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Related papers: On Curling Numbers of Integer Sequences

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Given a finite nonempty sequence of integers S, by grouping adjacent terms it is always possible to write it, possibly in many ways, as S = X Y^k, where X and Y are sequences and Y is nonempty. Choose the version which maximizes the value…

Combinatorics · Mathematics 2013-02-19 Benjamin Chaffin , N. J. A. Sloane

Given a finite nonempty sequence $S$ of integers, write it as $XY^k$, where $Y^k$ is a power of greatest exponent that is a suffix of $S$: this $k$ is the curling number of $S$. The concept of curling number of sequences has already been…

General Mathematics · Mathematics 2015-11-18 Susanth C. , Sunny Joseph Kalayathankal , N. K. Sudev , K. P. Chithra , Johan Kok

Given a finite nonempty sequence $S$ of integers, write it as $XY^k$, consisting of a prefix $X$ (which may possibly be empty), followed by $k$ copies of a non-empty string $Y$. Then, the greatest such integer $k$ is called the curling…

General Mathematics · Mathematics 2016-06-22 Susanth C , Sunny Joseph Kalayathankal , N. K. Sudev , K. P. Chithra , Johan Kok

Let $S=S_1S_2S_3\ldots S_n$ be a finite string. Write $S$ in the form $XYY\ldots Y=XY^k$, consisting of a prefix $X$ (which may be empty), followed by $k$ copies of a non-empty string $Y$. Then, the greatest value of this integer $k$ is…

General Mathematics · Mathematics 2016-08-10 N. K. Sudev , C. Susanth , K. P. Chithra , Johan Kok , Sunny Joseph Kalayathankal

The sequence starts with a(1) = 1; to extend it one writes the sequence so far as XY^k, where X and Y are strings of integers, Y is nonempty and k is as large as possible: then the next term is k. The sequence begins 1, 1, 2, 1, 1, 2, 2, 2,…

Let $s(n)$ be the number of different remainders $n \bmod k$, where $1 \leq k \leq \lfloor n/2 \rfloor$. This rather natural sequence is sequence A283190 in the OEIS and while some basic facts are known, it seems that surprisingly it has…

Number Theory · Mathematics 2025-08-29 Omkar Baraskar , Ingrid Vukusic

In this paper, we introduce the concept of curling subsequence of simple, finite and connected graphs. A curling subsequence is a maximal subsequence $C$ of the degree sequence of a simple connected graph $G$ for which the curling number…

Combinatorics · Mathematics 2015-07-08 Johan Kok , Naduvath Sudev , Chithra Sudev

Let $S= \{ p_1, \ldots, p_s\}$ be a finite, non-empty set of distinct prime numbers and $(U_{n})_{n \geq 0}$ be a linear recurrence sequence of integers of order $r$. For any positive integer $k,$ we define $(U_j^{(k)})_{j\geq 1}$ an…

Number Theory · Mathematics 2020-04-16 S. S. Rout , N. K. Meher

On the set of positive integers, we consider the iterative process that maps $n$ to either $\frac{3n+1}{2}$ or $\frac{n}{2}$ depending on the parity of $n$. The Collatz conjecture states that all such sequences eventually enter the trivial…

General Mathematics · Mathematics 2026-05-19 Olivier Rozier , Claude Terracol

We generalize the Stirling numbers of the first kind $s(a,k)$ to the case where $a$ may be an arbitrary real number. In particular, we study the case in which $a$ is an integer. There, we discover new combinatorial properties held by the…

Combinatorics · Mathematics 2008-02-03 Daniel E. Loeb

The 3n+1, or Collatz problem, is one of the hardest math problems, yet still unsolved. The Collatz conjecture is to prove or disprove that the Collatz sequences COL(n) always eventually reach the number of 1, for all n belongs to N+ (all…

General Mathematics · Mathematics 2025-06-17 Chin-Long Wey

In this paper; we prove that all sequences can be broken up in cycles. Each cycle follows the same pattern: 1) Upward trajectory. Odd and even numbers alternate until the cycle reaches an upper bound 2) Downward trajectory. Two or more…

General Mathematics · Mathematics 2025-03-24 Vicente Padilla

We introduce a new class of problems lying halfway between questions about graph capacity and intersection. We say that two binary sequences x and y of the same length have a skewincidence if there is a coordinate i for which x_i=y_{i+1}=1…

Combinatorics · Mathematics 2010-03-23 Gerard Cohen , Emanuela Fachini , Janos Korner

We prove a conjecture that classifies exceptional numbers. This conjecture arises in two different ways, from cryptography and from coding theory. An odd integer $t\geq 3$ is said to be exceptional if $f(x)=x^t$ is APN (Almost Perfect…

Information Theory · Computer Science 2024-05-01 Fernando Hernando , Gary McGuire

We prove a number of results related to a problem of Po-Shen Loh, which is equivalent to a problem in Ramsey theory. Let $a=(a_1,a_2,a_3)$ and $b=(b_1,b_2,b_3)$ be two triples of integers. Define $a$ to be 2-less than $b$ if $a_i<b_i$ for…

Combinatorics · Mathematics 2023-06-22 W. T. Gowers , J. Long

The Collatz conjecture (or ``Syracuse problem'') considers recursively-defined sequences of positive integers where $n$ is succeeded by $\tfrac{n}{2}$, if $n$ is even, or $\tfrac{3n+1}{2}$, if $n$ is odd. The conjecture states that for all…

Number Theory · Mathematics 2023-04-05 Christian Hercher

The ``comma sequence'' starts with 1 and is defined by the property that if k and k' are consecutive terms, the two-digit number formed from the last digit of k and the first digit of k' is equal to the difference k'-k. If there is more…

Number Theory · Mathematics 2024-05-28 Eric Angelini , Michael S. Branicky , Giovanni Resta , N. J. A. Sloane , David W. Wilson

We consider the length L of the longest common subsequence of two randomly uniformly and independently chosen n character words over a k-ary alphabet. Subadditivity arguments yield that the expected value of L, when normalized by n,…

Combinatorics · Mathematics 2007-05-23 Marcos Kiwi , Martin Loebl , Jiri Matousek

We establish new upper bounds for the length of runs of consecutive positive integers each with exactly $k$ divisors, where $k$ is a given positive integer of some special forms. Also we have found exact values of the maximum possible runs…

Number Theory · Mathematics 2018-11-14 Vasilii A. Dziubenko , Vladimir A. Letsko

Motivated by a WhattsApp message, we find out the integers $x> y\ge 1$ such that $(x+1)/(y+1)=(x\circ(y+1))/(y\circ (x+1))$, where $\circ$ means the concatenation of the strings of two natural numbers (for instance $783\circ 56=78356$). The…

Number Theory · Mathematics 2021-03-10 Josep M. Brunat , Joan-Carles Lario
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