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For a finite group $G$, a Tambara functor on $G$ is regarded as a $G$-bivariant analog of a commutative ring. In this analogy, previously we have defined an ideal of a Tambara functor. In this article, we will demonstrate a calculation of…

Group Theory · Mathematics 2013-01-09 Hiroyuki Nakaoka

For a finite group $G$, a semi-Mackey (resp. Tambara) functor is regarded as a $G$-bivariant analog of a commutative monoid (resp. ring). As such, some naive algebraic constructions are generalized to this $G$-bivariant setting. In this…

Category Theory · Mathematics 2011-03-22 Hiroyuki Nakaoka

Bi-incomplete Tambara functors are equivariant generalizations of commutative rings. The most common forms of bi-incomplete Tambara functors are coefficient systems of commutative rings, Green functors, and Tambara functors. In the 1980s,…

Algebraic Topology · Mathematics 2026-05-11 Scott Balchin , J. D. Quigley , Ben Spitz

Tambara functors are an equivariant generalization of rings that appear as the homotopy groups of genuine equivariant commutative ring spectra. In recent work, Blumberg and Hill have studied the corresponding algebraic structures, called…

Algebraic Topology · Mathematics 2024-01-31 David Chan

We compute the spectrum of prime ideals in the Burnside Tambara functor over an arbitrary finite group. Our proof uses recent advances in the commutative algebra of Tambara functors, as well as a Tambara functor analogue of ghost…

Algebraic Topology · Mathematics 2026-01-30 Maxine Elena Calle , David Chan , David Mehrle , J. D. Quigley , Ben Spitz , Danika Van Niel

Let $G$ be a finite group. A $G$-Tambara functor can be defined as a product-preserving functor $\mathcal{P}_G \to \mathsf{Set}$ (satisfying one additional condition), where $\mathcal{P}_G$ is a category that is constructed in a…

Algebraic Topology · Mathematics 2024-09-23 Ben Spitz

For a finite group $G$, (semi-)Mackey functors and (semi-)Tambara functors are regarded as $G$-bivariant analogs of (semi-)groups and (semi-)rings respectively. In fact if $G$ is trivial, they agree with the ordinary (semi-)groups and…

Category Theory · Mathematics 2011-05-25 Hiroyuki Nakaoka

We derive a family of prime ideals of the Burnside Tambara functor for a finite group $G$. In the case of cyclic groups, this family comprises the entire prime spectrum. We include some partial results towards the same result for a larger…

Group Theory · Mathematics 2024-02-26 Maxine Calle , Sam Ginnett

For an arbitrary group $G$, a (semi-)Mackey functor is a pair of covariant and contravariant functors from the category of $G$-sets, and is regarded as a $G$-bivariant analog of a commutative (semi-)group. In this view, a $G$-bivariant…

Category Theory · Mathematics 2010-10-06 Hiroyuki Nakaoka

We give, for every finite group G, a combinatorial description of the ring of G-Witt vectors on a polynomial algebra over the integers. Using this description we show that the functor, which takes a ring with trivial action of G to its ring…

Commutative Algebra · Mathematics 2007-05-23 Morten Brun

We define the notion of an $\mathcal{RO}(G)$-graded Tambara functor and prove that any $G$-spectrum with norm multiplication gives rise to such an $\mathcal{RO}(G)$-graded Tambara functor.

Algebraic Topology · Mathematics 2023-03-14 Vigleik Angeltveit , Anna Marie Bohmann

Tambara functors are the analogue of commutative rings in equivariant algebra. Nakaoka defined ideals in Tambara functors, leading to the definition of the Nakaoka spectrum of prime ideals in a Tambara functor. In this work, we continue the…

Algebraic Topology · Mathematics 2026-03-13 David Chan , David Mehrle , J. D. Quigley , Ben Spitz , Danika Van Niel

We survey and extend the theory of Tambara functors. These are algebraic structures similar to Mackey functors, but with multiplicative norm maps as well as additive transfer maps, and a rule governing their interaction that is most easily…

Algebraic Topology · Mathematics 2012-05-14 Neil Strickland

For all subgroups $H$ of a cyclic $p$-group $G$ we define norm functors that build a $G$-Mackey functor from an $H$-Mackey functor. We give an explicit construction of these functors in terms of generators and relations based solely on the…

Algebraic Topology · Mathematics 2019-08-02 Michael A. Hill , Kristen Mazur

Tambara functors arise in equivariant homotopy theory as the structure adherent to the homotopy groups of a coherently commutative equivariant ring spectrum. We show that if $k$ is a field-like $C_{p^n}$-Tambara functor, then $k$ is the…

Algebraic Topology · Mathematics 2025-03-07 Noah Wisdom

Associated to each Tambara functor $T$ is its Nakaoka spectrum $\mathrm{Spec}(T)$, analogous to the Zariski spectrum of a commutative ring. We establish that this topological space is spectral. This result follows from an analysis of the…

Algebraic Topology · Mathematics 2026-02-02 David Chan , Ben Spitz

This paper explores the Tambara functor structure of the trace ideal of a Galois extension. In the case of a (pro-)cyclic extension, we are able to explicitly determine the generators of the ideal. Furthermore, we show that the absolute…

Number Theory · Mathematics 2024-03-08 Maxine Calle , Sam Ginnett , Harry Chen , Xinling Chen

Tambara functors are equivariant analogues of rings arising in representation theory and equivariant homotopy theory. We introduce the notion of a clarified Tambara functor and show that under mild conditions every Tambara functor admits a…

Algebraic Topology · Mathematics 2025-08-14 Noah Wisdom

It is well known that the zeroth stable homotopy group of a genuine equivariant commutative ring spectrum has multiplicative transfers (norms), making it into a Tambara functor. We prove here that all Tambara functors can be obtained in…

Algebraic Topology · Mathematics 2013-05-23 John Ullman

Let $G$ be a finite group, and $k$ an integer. In this note, we show that for any $G$-Tambara functor $T$ and any subgroups $H_1, H_2 \leq G$, $k$ is a unit in $T(G/H_1)$ if and only if $k$ is a unit in $T(G/H_2)$. In other words, one may…

Group Theory · Mathematics 2026-01-27 Ben Spitz
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