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Related papers: Enumerating (2+2)-free posets by indistinguishable…

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An unlabeled poset is said to be (2+2)-free if it does not contain an induced subposet that is isomorphic to 2+2, the union of two disjoint 2-element chains. Let $p_n$ denote the number of (2+2)-free posets of size $n$. In a recent paper,…

Combinatorics · Mathematics 2010-04-20 Sergey Kitaev , Jeffrey Remmel

Recently, Kitaev and Remmel posed a conjecture concerning the generating function for the number of unlabeled $(2+2)$-free posets with respect to number of elements and number of minimal elements. In this paper, we present a combinatorial…

Combinatorics · Mathematics 2010-06-17 Sherry H. F. Yan

We present bijections between four classes of combinatorial objects. Two of them, the class of unlabeled (2+2)-free posets and a certain class of involutions (or chord diagrams), already appeared in the literature, but were apparently not…

Combinatorics · Mathematics 2025-09-26 Mireille Bousquet-Mélou , Anders Claesson , Mark Dukes , Sergey Kitaev

A poset is (3+1)-free if it does not contain the disjoint union of chains of length 3 and 1 as an induced subposet. These posets play a central role in the (3+1)-free conjecture of Stanley and Stembridge. Lewis and Zhang have enumerated…

Combinatorics · Mathematics 2015-12-31 Mathieu Guay-Paquet , Alejandro H. Morales , Eric Rowland

We show that there are $n!$ matchings on $2n$ points without, so called, left (neighbor) nestings. We also define a set of naturally labeled $(2+2)$-free posets, and show that there are $n!$ such posets on $n$ elements. Our work was…

Combinatorics · Mathematics 2010-07-14 Anders Claesson , Svante Linusson

A poset is (3+1)-free if it does not contain the disjoint union of chains of length 3 and 1 as an induced subposet. These posets are the subject of the (3+1)-free conjecture of Stanley and Stembridge. Recently, Lewis and Zhang have…

Combinatorics · Mathematics 2014-04-18 Mathieu Guay-Paquet , Alejandro H. Morales , Eric Rowland

A poset is {\it $(\3+\1)$-free} if it contains no induced subposet isomorphic to the disjoint union of a 3-element chain and a 1-element chain. These posets are of interest because of their connection with interval orders and their…

Combinatorics · Mathematics 2011-03-01 M. D. Atkinson , Bruce E. Sagan , Vincent Vatter

A poset has the non-messing-up property if it has two covering sets of disjoint saturated chains so that for any labeling of the poset, sorting the labels along one set of chains and then sorting the labels along the other set yields a…

Combinatorics · Mathematics 2010-09-23 Bridget Eileen Tenner

In the area of forbidden subposet problems we look for the largest possible size $La(n,P)$ of a family $\mathcal{F}\subseteq 2^{[n]}$ that does not contain a forbidden inclusion pattern described by $P$. The main conjecture of the area…

Combinatorics · Mathematics 2020-07-15 Dániel Gerbner , Dániel Nagy , Balázs Patkós , Máté Vizer

This paper introduces the concept of a generating set for stochastic matrices -- a subset of matrices whose repeated composition generates the entire set. Understanding such generating sets requires specifying the "indivisible elements" and…

Rings and Algebras · Mathematics 2025-02-04 Frederik vom Ende , Fereshte Shahbeigi

We say a finite poset $P$ is a tree poset if its Hasse diagram is a tree. Let $k$ be the length of the largest chain contained in $P$. We show that when $P$ is a fixed tree poset, the number of $P$-free set systems in $2^{[n]}$ is…

Combinatorics · Mathematics 2024-12-24 József Balogh , Ramon I. Garcia , Michael C. Wigal

We establish formulas for the number of all downsets (or equivalently, of all antichains) of a finite poset P. Then, using these numbers, we determine recursively and explicitly the number of all posets having a fixed set of minimal points…

Combinatorics · Mathematics 2018-02-06 Frank A Campo , Marcel Erné

Let $B_n$ be the poset generated by the subsets of $[n]$ with the inclusion as relation and let $P$ be a finite poset. We want to embed $P$ into $B_n$ as many times as possible such that the subsets in different copies are incomparable. The…

Combinatorics · Mathematics 2013-10-01 Gyula O. H. Katona , Dániel T. Nagy

A matching of the set $[2n]=\{ 1,2,\ldots ,2n\}$ is a partition of $[2n]$ into blocks with two elements, i.e. a graph on $[2n]$ such that every vertex has degree one. Given two matchings $\sigma$ and $\tau$ , we say that $\sigma$ is a…

Combinatorics · Mathematics 2020-09-03 Matteo Cervetti , Luca Ferrari

We propose a matrix approach for generating naturally labeled posets by representing each poset $P$ on the set $[n]$ as a Boolean poset matrix $A$. This algebraic representation enables a systematic handling of partial orderings through…

Combinatorics · Mathematics 2026-05-19 Gi-Sang Cheon , Samuele Giraudo , Gukwon Kwon , Hojoon Lee

The $P$-partition generating function of a (naturally labeled) poset $P$ is a quasisymmetric function enumerating order-preserving maps from $P$ to $\mathbb{Z}^+$. Using the Hopf algebra of posets, we give necessary conditions for two…

Combinatorics · Mathematics 2019-09-17 Ricky Ini Liu , Michael Weselcouch

We develop a powerful tool for embedding any tree poset $P$ of height $k$ in the Boolean lattice which allows us to solve several open problems in the area. We show that: * If $H$ is a family in $B_n$ with $|H|\ge (q-1+\varepsilon){n\choose…

Combinatorics · Mathematics 2025-10-15 Tao Jiang , Sean Longbrake , Sam Spiro , Liana Yepremyan

Let $F$ be a field. We show that the largest irredundant generating sets for the algebra of $n\times n $ matrices over $F$ have $2n-1$ elements when $n>1$. (A result of Laffey states that the answer is $2n-2$ when $n>2$, but its proof…

Rings and Algebras · Mathematics 2025-04-04 Yonatan Blumenthal , Uriya First

We consider sets of positive integers containing no sum of two elements in the set and also no product of two elements. We show that the upper density of such a set is strictly smaller than 1/2 and that this is best possible. Further, we…

Number Theory · Mathematics 2013-09-10 Par Kurlberg , Jeffrey C. Lagarias , Carl Pomerance

We classify finite posets with a particular sorting property, generalizing a result for rectangular arrays. Each poset is covered by two sets of disjoint saturated chains such that, for any original labeling, after sorting the labels along…

Combinatorics · Mathematics 2007-05-23 Bridget Eileen Tenner
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