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A poset is (3+1)-free if it does not contain the disjoint union of chains of length 3 and 1 as an induced subposet. These posets play a central role in the (3+1)-free conjecture of Stanley and Stembridge. Lewis and Zhang have enumerated…

Combinatorics · Mathematics 2015-12-31 Mathieu Guay-Paquet , Alejandro H. Morales , Eric Rowland

We study three different poset structures on the set of all compositions. In the first case, the covering relation consists of inserting a part of size one to the left or to the right, or increasing the size of some part by one. The…

Combinatorics · Mathematics 2007-05-23 Jan Snellman

Given a poset $P$ we say a family $\mathcal{F}\subseteq P$ is centered if it is obtained by `taking sets as close to the middle layer as possible'. A poset $P$ is said to have the centeredness property if for any $M$, among all families of…

Combinatorics · Mathematics 2020-05-14 Jozsef Balogh , Sarka Petrickova , Adam Zsolt Wagner

Graded posets frequently arise throughout combinatorics, where it is natural to try to count the number of elements of a fixed rank. These counting problems are often $\#\textbf{P}$-complete, so we consider approximation algorithms for…

Data Structures and Algorithms · Computer Science 2023-04-11 Prateek Bhakta , Ben Cousins , Matthew Fahrbach , Dana Randall

A poset is (3+1)-free if it does not contain the disjoint union of chains of length 3 and 1 as an induced subposet. These posets are the subject of the (3+1)-free conjecture of Stanley and Stembridge. Recently, Lewis and Zhang have…

Combinatorics · Mathematics 2014-04-18 Mathieu Guay-Paquet , Alejandro H. Morales , Eric Rowland

We present results on the enumeration of crossings and nestings for matchings and set partitions. Using a bijection between partitions and vacillating tableaux, we show that if we fix the sets of minimal block elements and maximal block…

Combinatorics · Mathematics 2007-05-23 William Y. C. Chen , Eva Y. P. Deng , Rosena R. X. Du , Richard P. Stanley , Catherine H. Yan

How many matchings on the vertex set V={1,2,...,2n} avoid a given configuration of three edges? Chen, Deng and Du have shown that the number of matchings that avoid three nesting edges is equal to the number of matchings avoiding three…

Combinatorics · Mathematics 2007-06-26 Vit Jelinek

Given a symmetric monoidal category $C$ with product $\sqcup$, where the neutral element for the product is an initial object, we consider the poset of $\sqcup$-complemented subobjects of a given object $X$. When this poset has finite…

Combinatorics · Mathematics 2025-07-30 Kevin Ivan Piterman , Volkmar Welker

We introduce two partially ordered sets, $P^A_n$ and $P^B_n$, of the same cardinalities as the type-A and type-B noncrossing partition lattices. The ground sets of $P^A_n$ and $P^B_n$ are subsets of the symmetric and the hyperoctahedral…

Combinatorics · Mathematics 2007-05-23 Miklós Bóna , Rodica Simion

We propose a matrix approach for generating naturally labeled posets by representing each poset $P$ on the set $[n]$ as a Boolean poset matrix $A$. This algebraic representation enables a systematic handling of partial orderings through…

Combinatorics · Mathematics 2026-05-19 Gi-Sang Cheon , Samuele Giraudo , Gukwon Kwon , Hojoon Lee

We say a natural number $n$ is matchable if there is a bijection from the set of $\tau(n)$ divisors of $n$ to the set $\{1,2,\dots,\tau(n)\}$, where corresponding numbers are relatively prime. We show that the set of matchable numbers has…

Number Theory · Mathematics 2026-05-26 Nathan McNew , Carl Pomerance

Consider the problem of finding high dimensional approximate nearest neighbors, where the data is generated by some known probabilistic model. We will investigate a large natural class of algorithms which we call bucketing codes. We will…

Information Theory · Computer Science 2016-11-17 Moshe Dubiner

We enumerate bijectively the family of involutive Baxter permutations according to various parameters; in particular we obtain an elementary proof that the number of involutive Baxter permutations of size $2n$ with no fixed points is…

Combinatorics · Mathematics 2011-10-31 Eric Fusy

We show that plane bipolar posets (i.e., plane bipolar orientations with no transitive edge) and transversal structures can be set in correspondence to certain (weighted) models of quadrant walks, via suitable specializations of a bijection…

Combinatorics · Mathematics 2023-10-03 Éric Fusy , Erkan Narmanli , Gilles Schaeffer

A well-labelled positive path of size n is a pair (p,\sigma) made of a word p=p_1p_2...p_{n-1} on the alphabet {-1, 0,+1} such that the sum of the letters of any prefix is non-negative, together with a permutation \sigma of {1,2,...,n} such…

Combinatorics · Mathematics 2010-10-04 Olivier Bernardi , Bertrand Duplantier , Philippe Nadeau

Ascent sequences are sequences of nonnegative integers with restrictions on the size of each letter, depending on the number of ascents preceding it in the sequence. Ascent sequences have recently been related to (2+2)-free posets and…

Combinatorics · Mathematics 2011-11-01 Paul Duncan , Einar Steingrimsson

We introduce iposets---posets with interfaces---equipped with a novel gluing composition along interfaces and the standard parallel composition. We study their basic algebraic properties as well as the hierarchy of gluing-parallel posets…

Formal Languages and Automata Theory · Computer Science 2019-10-15 Uli Fahrenberg , Christian Johansen , Georg Struth , Ratan Bahadur Thapa

A poset has the non-messing-up property if it has two covering sets of disjoint saturated chains so that for any labeling of the poset, sorting the labels along one set of chains and then sorting the labels along the other set yields a…

Combinatorics · Mathematics 2010-09-23 Bridget Eileen Tenner

We have extended classical pattern avoidance to a new structure: multiple task-precedence posets whose Hasse diagrams have three levels, which we will call diamonds. The vertices of each diamond are assigned labels which are compatible with…

Combinatorics · Mathematics 2023-06-22 Mitchell Paukner , Lucy Pepin , Manda Riehl , Jarred Wieser

We give a bijective proof of the Aztec diamond theorem, stating that there are $2^{n(n+1)/2}$ domino tilings of the Aztec diamond of order $n$. The proof in fact establishes a similar result for non-intersecting families of $n+1$ Schr\"oder…

Combinatorics · Mathematics 2012-09-25 Frédéric Bosio , Marc A. A. Van Leeuwen