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Let $H$ be a connected reductive subgroup of a complex connected reductive group $G$. Fix maximal tori and Borel subgroups of $H$ and $G$. Consider the pairs $(V,V')$ of irreducible representations of $H$ and $G$ such that $V$ is a…

Algebraic Geometry · Mathematics 2010-09-15 Nicolas Ressayre

Let X=G/B be a complete flag variety, and L' and L" two line bundles on X. Consider the cup product map H^{d'}(X,L') x H^{d"}(X, L") --> H^{d}(X,L), where L=L' x L" and d=d'+d". We answer two natural questions about the map above: When is…

Algebraic Geometry · Mathematics 2017-06-28 Ivan Dimitrov , Mike Roth

Let G be a complex connected reductive group. The PRV conjecture, which was proved independently by S. Kumar and O. Mathieu in 1989, gives explicit irreducible submodules of the tensor product of two irreducible G-modules. This paper has…

Representation Theory · Mathematics 2019-02-20 Pierre-Louis Montagard , Boris Pasquier , Nicolas Ressayre

Let $G\subset\hat{G}$ be two complex connected reductive groups. We deals with the hard problem of finding sub-$G$-modules of a given irreducible $\hat{G}$-module. In the case where $G$ is diagonally embedded in $\hat{G}=G\times G$, S.…

Representation Theory · Mathematics 2011-10-21 Pierre-Louis Montagard , Boris Pasquier , Nicolas Ressayre

We consider the groups G which arise from real semisimple Jordan algebras via the Tits-Koecher-Kantor construction. Such a G is characterized by the fact that it admits a parabolic subgroup P=LN which is conjugate to its opposite, and for…

Representation Theory · Mathematics 2016-09-07 Alexander Dvorsky , Siddhartha Sahi

Answering the question of A. Joseph, for every pair $(G, V)$ where $G$ is a connected simple linear algebraic group and $V$ is a simple algebraic $G$-module with a free algebra of invariants, the number of irreducible components of the…

Algebraic Geometry · Mathematics 2015-03-31 Vladimir L. Popov

Let G be a connected semisimple complex algebraic group and let P be a parabolic subgroup. In this paper we define a new (commutative and associative) product on the cohomology of the homogenous spaces G/P and use this to give a more…

Algebraic Geometry · Mathematics 2016-09-07 Prakash Belkale , Shrawan Kumar

Let $G$ be a connected reductive subgroup of a complex connected reductive group $\hat{G}$. Fix maximal tori and Borel subgroups of $G$ and $\hat{G}$. Consider the cone $LR^\circ(\hat{G},G)$ generated by the pairs $(\nu,\hat{\nu})$ of…

Algebraic Geometry · Mathematics 2015-05-13 Nicolas Ressayre

Let $G_1,G_2$ be real reductive groups and $(\pi,V)$ a smooth, irreducible, admissible representation of $G_1 \times G_2$. We prove that $(\pi,V)$ is the completed tensor product of $(\pi_i,V_i)$, $i=1,2$, where $(\pi_i,V_i)$ is a…

Representation Theory · Mathematics 2012-12-27 Dmitry Gourevitch , Alexander Kemarsky

Let G be a simple, simply connected and connected algebraic group over an algebraically closed field of characteristic p>0, and let V be a rational G-module such that dim V <= p. According to a result of Jantzen, V is completely reducible,…

Representation Theory · Mathematics 2007-05-23 George J. McNinch

The set of possible spectra (\lambda,\mu,\nu) of zero-sum triples of Hermitian matrices forms a polyhedral cone. We give a complete determination of its facets, finishing a long story with recent highlights by [Helmke-Rosenthal, Klyachko,…

Combinatorics · Mathematics 2010-04-26 Allen Knutson , Terence Tao , Christopher Woodward

Let $F$ be a totally real field unramified at all places above $p$ and $D$ be a quaternion algebra which splits at either none, or exactly one, of the infinite places. Let $\bar{r}:\mathrm{Gal}(\bar{F}/F)\to…

Number Theory · Mathematics 2022-07-21 Yongquan Hu , Haoran Wang

Let $G$ be a simple, simply-connected complex algebraic group with Lie algebra $\mathfrak{g}$, and $G/B$ the associated complete flag variety. The Hochschild cohomology $HH^\bullet(G/B)$ is a geometric invariant of the flag variety related…

Representation Theory · Mathematics 2025-01-17 Sam Jeralds

We give a sufficient condition for a Littelmann path to represent a vector of extremal weight of an integrable irreducible highest weight representation of a symmetrisable Kac-Moody algebra. Thanks to this condition we present, in a more…

Representation Theory · Mathematics 2013-08-29 Pierre-Louis Montagard

Let $G=G_1 \times G_2$ be a finite group. We know that the second cohomology group $H^2(G,\mathbb C^\times)$ is isomorphic to $H^2(G_1,\mathbb C^\times) \times H^2(G_2,\mathbb C^\times) \times Hom(G_1/G_1' \otimes_\mathbb Z G_2/G_2',…

Representation Theory · Mathematics 2023-11-21 Sumana Hatui

Given a complex simple Lie algebra $\mathfrak{g}$ and a positive integer $\ell$, under the assumption $\lambda\gg\mu$, we show that irreducible representations of $\mathfrak{g}$ of the form $V(\lambda +w\mu)$, $w\in W,$ with level at most…

Representation Theory · Mathematics 2021-03-26 Arzu Boysal

Let $F$ be a totally real number field, $\wp$ a place of $F$ above $p$. Let $\rho$ be a $2$-dimensional $p$-adic representation of $\mathrm{Gal}(\bar{F}/F)$ which appears in the \'etale cohomology of quaternion Shimura curves (thus $\rho$…

Number Theory · Mathematics 2016-02-19 Yiwen Ding

Let $F$ be a non-Archimedean locally compact field and let $D$ be a central division algebra over $F$. Let $\pi_1$ and $\pi_2$ be respectively two smooth irreducible representations of ${\rm GL}(n_1,D)$ and ${\rm GL}(n_2,F)$, $n_1, n_2 \geq…

Representation Theory · Mathematics 2007-09-21 Alberto Minguez

Let $G$ be a complex semisimple algebraic group. In 2006, Belkale-Kumar defined a new product $odot\_0$ on thecohomology group $H^*(G/P,{\mathbb C})$ of any projective $G$-homogeneousspace $G/P$.Their definition uses the notion of…

Algebraic Geometry · Mathematics 2017-09-28 N Ressayre

The Belkale-Kumar product on H*(G/P) is a degeneration of the usual cup product on the cohomology ring of a generalized flag manifold. In the case G=GL_n, it was used by N. Ressayre to determine the regular faces of the…

Combinatorics · Mathematics 2010-10-05 Allen Knutson , Kevin Purbhoo
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