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We prove that many pretzel knots of the form $P(2n,m,-2n\pm1,-m)$ are not topologically slice, even though their positive mutants $P(2n, -2n\pm1, m, -m)$ are ribbon. We use the sliceness obstruction of Kirk and Livingston related to the…

Geometric Topology · Mathematics 2015-02-19 Allison N. Miller

Let p be an odd prime and D_p a dihedral group of order 2p. Let \rho: G(K) --> D_p --> GL(p,Z) be a non-abelian representation of the knot group G(K) of a knot K in 3-sphere. Let \Delta_{\rho,K} (t) be the twisted Alexander polynomial of K…

Geometric Topology · Mathematics 2009-03-03 Mikami Hirasawa , Kunio Murasugi

The twisted Alexander polynomial of a knot is defined associated to a linear representation of the knot group. If there exists a surjective homomorphism of a knot group onto a finite group, then we obtain a representation of the knot group…

Geometric Topology · Mathematics 2024-01-08 Takayuki Morifuji , Masaaki Suzuki

We calculate the twisted Alexander polynomials of $(-2,3,2n+1)$-pretzel knots associated to their holonomy representations. As a corollary, we obtain new supporting evidences of Dunfield, Friedl and Jackson's conjecture, that is, the…

Geometric Topology · Mathematics 2018-03-20 Airi Aso

The group of a nontrivial knot admits a finite permutation representation such that the corresponding twisted Alexander polynomial is not a unit.

Geometric Topology · Mathematics 2009-05-21 Daniel S Silver , Susan G Williams

In this paper we present a sequence of link invariants, defined from twisted Alexander polynomials, and discuss their effectiveness in distinguish knots. In particular, we recast and extend by geometric means a recent result of Silver and…

Geometric Topology · Mathematics 2018-12-24 Stefan Friedl , Stefano Vidussi

For any knot, the following are equivalent. (1) The infinite cyclic cover has uncountably many finite covers; (2) there exists a finite-image representation of the knot group for which the twisted Alexander polynomial vanishes; (3) the knot…

Geometric Topology · Mathematics 2014-02-26 Daniel S. Silver , Susan G. Williams

There are infinitely many pretzel links with the same Alexander polynomial (actually with trivial Alexander polynomial). By contrast, in this note we revisit the Jones polynomial of pretzel links and prove that, given a natural number S,…

Geometric Topology · Mathematics 2020-11-20 R. Díaz , P. M. G. Manchón

Suppose the knot group G(K) of a knot K has a non-abelian representation \rho on A_4 \subset GL(4,Z). We conjecture that the twisted Alexander polynomial of K associated to \rho is of the form: \Delta_K(t)/(1-t) \phi(t^3), where \Delta_K…

Geometric Topology · Mathematics 2009-03-11 Mikami Hirasawa , Kunio Murasugi

We provide explicit formulas for the Alexander polynomial of pretzel knots and establish several immediate corollaries, including the characterization of pretzel knots with a trivial Alexander polynomial. As an application, we construct a…

Geometric Topology · Mathematics 2026-03-10 Y. Belousov

In this paper we will study properties of twisted Alexander polynomials of knots corresponding to metabelian representations. In particular we answer a question of Wada about the twisted Alexander polynomial associated to the tensor product…

Geometric Topology · Mathematics 2021-03-16 Hans U. Boden , Stefan Friedl

Given a homomorphism from a knot group to a fixed group, we introduce an element of a $K_1$-group, which is a generalization of (twisted) Alexander polynomials. We compare this $K_1$-class with other Alexander polynomials. In terms of…

Geometric Topology · Mathematics 2020-11-24 Takefumi Nosaka

We study the asymptotic behavior of the twisted Alexander polynomial for the sequence of SL(n ,C)-representations induced from an irreducible metabelian SL(2, C)-representation of a knot group. We give the limits of the leading coefficients…

Geometric Topology · Mathematics 2016-08-22 Anh T. Tran , Yoshikazu Yamaguchi

Let K be a knot in $S^3$ and $X$ its complement. We study deformations of reducible metabelian representations of the knot group $\pi_1(X)$ into $SL(3,\mathbb{C})$ which are associated to a double root of the Alexander polynomial. We prove…

Geometric Topology · Mathematics 2008-10-16 Leila Ben Abdelghani , Michael Heusener , Hajer Jebali

For each even classical pretzel knot $P(2k_1+1,2k_2+1,2k_3)$, we determine the character variety of irreducible ${\rm SL}(2,\mathbb{C})$-representations, and clarify the steps of computing its A-polynomial.

Geometric Topology · Mathematics 2024-02-19 Haimiao Chen

In this paper, we discuss twisted Alexander polynomials of a knot for group extensions of a finite group in two directions. Firstly, we provide a mod $p$ formula for the twisted Alexander polynomial of a knot in the $3$-sphere associated…

Geometric Topology · Mathematics 2026-05-14 Katsumi Ishikawa , Takayuki Morifuji , Masaaki Suzuki

We observe the twisted Alexander polynomial for metabelian representations of knot groups into SL(2,C) and study relations to the characterizations of metabelian representations in the character varieties. We give a factorization of the…

Geometric Topology · Mathematics 2013-07-12 Yoshikazu Yamaguchi

We study a twisted Alexander polynomial naturally associated to a hyperbolic knot in an integer homology 3-sphere via a lift of the holonomy representation to SL(2, C). It is an unambiguous symmetric Laurent polynomial whose coefficients…

Geometric Topology · Mathematics 2014-07-31 Nathan M. Dunfield , Stefan Friedl , Nicholas Jackson

Let $K$ be a knot in $S^3$ and $X$ its complement. We study deformations of non-abelian, metabelian, reducible representations of the knot group $\pi\_1(X)$ into $\mathrm{SL}(n,\mathbf{C})$ which are associated to a simple root of the…

Geometric Topology · Mathematics 2015-02-16 Michael Heusener , Ouardia Medjerab

We study the twisted Alexander polynomial $\Delta_{K,\rho}$ of a knot $K$ associated to a non-abelian representation $\rho$ of the knot group into $SL_2(\BC)$. It is known for every knot $K$ that if $K$ is fibered, then for every…

Geometric Topology · Mathematics 2013-09-05 Anh T. Tran
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