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Related papers: Knots in Riemannian manifolds

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In this article it is proven that if a knot, K, bounds an imbedded grope of class n, then the knot is n/2-trivial in the sense of Gusarov and Stanford. That is, all type n/2 invariants vanish on K. We also give a simple way to construct all…

Geometric Topology · Mathematics 2007-05-23 James Conant

We introduce Riemannian metrics of positive scalar curvature on manifolds with Baas-Sullivan singularities, prove a corresponding homology invariance principle and discuss admissible products. Using this theory we construct positive scalar…

Differential Geometry · Mathematics 2021-04-07 Bernhard Hanke

We study closed non-positively curved Riemannian manifolds $M$ which admit `fat $k$-flats': that is, the universal cover $\tilde M$ contains a positive radius neighborhood of a $k$-flat on which the sectional curvatures are identically…

Dynamical Systems · Mathematics 2024-12-02 D. Constantine , J. -F. Lafont , D. B. McReynolds , D. J. Thompson

We consider slice disks for knots in the boundary of a smooth compact 4-manifold $X^{4}$. We call a knot $K \subset \partial X$ deep slice in $X$ if there is a smooth properly embedded 2-disk in $X$ with boundary $K$, but $K$ is not…

Geometric Topology · Mathematics 2021-06-11 Michael Klug , Benjamin Ruppik

For every $n \geq 4$, we demonstrate the existence of non-isotopic smooth $(n-2)$-knots in $S^n$ with diffeomorphic traces by generalising the RBG link construction to all dimensions. Conversely, we prove that for every $n \geq 4$, the…

We prove that a topological 4-manifold of globally non-positive curvature is homeomorphic to Euclidean space.

Differential Geometry · Mathematics 2021-09-21 Alexander Lytchak , Koichi Nagano , Stephan Stadler

A special case of the main result states that a complete $1$-connected Riemannian manifold $(M^n,g)$ is isometric to one of the models $\mathbb R^n$, $S^n(c)$, $\mathbb H^n(-c)$ of constant curvature if and only if every $p\in M^n$ is a…

Differential Geometry · Mathematics 2020-05-05 Xiaoyang Chen , Francisco Fontenele , Frederico Xavier

We generalize the results of [AS], finding large classes of totally geodesic Seifert surfaces in hyperbolic knot and link complements, each the lift of a rigid 2-orbifold embedded in some hyperbolic 3-orbifold. In addition, we provide a…

By using double branched covers, we prove that there is a 1-1 correspondence between the set of knotoids in the 2-sphere, up to orientation reversion and rotation, and knots with a strong inversion, up to conjugacy. This correspondence…

Geometric Topology · Mathematics 2019-09-26 Agnese Barbensi , Dorothy Buck , Heather A. Harrington , Marc Lackenby

A slope $p/q \in \mathbb{Q}$ is characterising for a knot $K \subset \mathbb{S}^3$ if the oriented homeomorphism type of the manifold $\mathbb{S}^3_K(p/q)$ obtained by Dehn surgery of slope $p/q$ on $K$ uniquely determines the knot $K$. We…

Geometric Topology · Mathematics 2026-03-04 Laura Wakelin

We investigate L-sectional curvature of S-manifolds with respect to the Rieman- nian connection and to certain semi-symmetric metric and non-metric connections naturally related with the structure, obtaining conditions for them to be…

Differential Geometry · Mathematics 2013-04-23 Mehmet Akif Akyol , Luis M. FernÁndez , Alicia Prieto-MartÍn

We study two sorts of actions on the space of conjugacy classes of irreducible $SU_2$-representations of a knot group. One of them is an involution which comes from the algebraic structure of $SU_2$ and the other is the action by the outer…

Geometric Topology · Mathematics 2009-09-17 Takahiro Kitayama

Let $K_0$ and $K$ be knots in $\mathbb{R}^3$. Suppose that by a compactly supported Hamiltonian isotopy on $T^*\mathbb{R}^3$, the conormal bundle of $K_0$ is isotopic to a Lagrangian submanifold which intersects the zero section cleanly…

Symplectic Geometry · Mathematics 2025-04-29 Yukihiro Okamoto

In this article, we propose a new approach for describing and understanding knots and links in a 3-manifold through the use of an embedded non-orientable surface. Specifically, we define a plat-like representation based on this…

Geometric Topology · Mathematics 2025-03-04 Alessia Cattabriga , Paolo Cavicchioli , Rama Mishra , Visakh Narayanan

Using spinning we analyze in a geometric way Haefliger's smoothly knotted (4k-1)-spheres in the 6k-sphere. Consider the 2-torus standardly embedded in the 3-sphere, which is further standardly embedded in the 6-sphere. At each point of the…

Geometric Topology · Mathematics 2014-10-01 Dennis Roseman , Masamichi Takase

In this paper, we are able to prove an analogy of the Calabi-Yau theorem for complete Riemannian manifolds with nonnegative scalar curvature which are aspherical at infinity. The key tool is an existence result for arbitrarily large bounded…

Differential Geometry · Mathematics 2024-02-26 Jintian Zhu

Let (M^n_i,g_i,p_i) be a sequence of smooth pointed complete n-dimensional Riemannian Manifolds with uniform bounds on the sectional curvatures and let (X,d,p) be a metric space such that (M^n_i,g_i,p_i) -> (X,d,p) in the Gromov-Hausdorff…

Differential Geometry · Mathematics 2008-06-18 Aaron Naber , Gang Tian

A Riemannian manifold is said to be almost positively curved if the sets of points for which all $2$-planes have positive sectional curvature is open and dense. We show that the Grassmannian of oriented $2$-planes in $\mathbb{R}^7$ admits a…

Differential Geometry · Mathematics 2021-07-08 Jason DeVito , Ezra Nance

Let M be a Riemannian n-manifold with n greater than or equal to 3. For k between 1 and n, we say M has k-positive Ricci curvature if at every point of M the sum of any k eigenvalues of the Ricci curvature is strictly positive. In…

Differential Geometry · Mathematics 2020-05-05 Jon Wolfson

Given any nondegenerate k-dimensional minimal submanifold K of codimension greater than 1, we prove the existence of families of constant mean curvature submanifolds, with mean curvature varying from one member of the family to another,…

Differential Geometry · Mathematics 2007-05-23 Fethi Mahmoudi , Rafe Mazzeo , Frank Pacard
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