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Related papers: Nonfibered knots and representation shifts

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An almost-fibered knot is a knot whose complement possesses a circular thin position in which there is one and only one weakly incompressible Seifert surface and one incompressible Seifert surface. Infinite examples of almost-fibered knots…

Geometric Topology · Mathematics 2024-03-19 Mario Eudave-Muñoz , Araceli Guzmán-Tristán , Enrique Ramírez-Losada

It is shown, using sutured manifold theory, that if there are any 2-component counterexamples to the Generalized Property R Conjecture, then any knot of least genus among components of such counterexamples is not a fibered knot. The general…

Geometric Topology · Mathematics 2009-01-16 Martin Scharlemann , Abigail Thompson

We show that the commutator subgroup G' of a classical knot group G need not have subgroups of every finite index, but it will if G' has a surjective homomorphism to the integers and we give an exact criterion for that to happen. We also…

Geometric Topology · Mathematics 2007-05-23 J. O. Button

By a recent result of Livingston, it is known that if a knot has a prime power branched cyclic cover that is not a homology sphere, then there is an infinite family of non-concordant knots having the same Seifert form as the knot. In this…

Geometric Topology · Mathematics 2007-05-23 Taehee Kim

We construct an infinite family of knots in rational homology spheres with irreducible, non-fibered complements, for which every non-longitudinal filling is an L-space.

Geometric Topology · Mathematics 2016-01-20 Tye Lidman , Liam Watson

We show that a knot in $S^3$ with an infinite number of distinct incompressible Seifert surfaces contains a closed incompressible surface in its complement.

Geometric Topology · Mathematics 2007-05-23 Robin T. Wilson

It is well known that there exist knots with Seifert surfaces of arbitrarily high genus. In this paper, we show the existence of infinitely many knot exteriors where each of which has longitudinal essential surfaces of any positive genus…

Geometric Topology · Mathematics 2025-08-26 Joao M. Nogueira

Hempel has shown that the fundamental groups of knot complements are residually finite. This implies that every nontrivial knot must have a finite-sheeted, noncyclic cover. We give an explicit bound, $\Phi (c)$, such that if $K$ is a…

Geometric Topology · Mathematics 2014-06-10 Nathan Broaddus

For any knot, the following are equivalent. (1) The infinite cyclic cover has uncountably many finite covers; (2) there exists a finite-image representation of the knot group for which the twisted Alexander polynomial vanishes; (3) the knot…

Geometric Topology · Mathematics 2014-02-26 Daniel S. Silver , Susan G. Williams

If a knot K has Seifert matrix V_K and has a prime power cyclic branched cover that is not a homology sphere, then there is an infinite family of non-concordant knots having Seifert matrix V_K.

Geometric Topology · Mathematics 2014-11-11 Charles Livingston

We introduce a new algebraic topological technique to detect non-fibred knots in the three sphere using the twisted Alexander invariants. As an application, we show that for any Seifert matrix of a knot with a nontrivial Alexander…

Geometric Topology · Mathematics 2007-05-23 Jae Choon Cha

Harvey-Kawamuro-Plamenevskaya demonstrated the existence of (transversely) non-isotopic transverse knots such that for every $n>1$ their $n$-fold cyclic branched covers are contactomorphic. In this short note, we construct other examples of…

Geometric Topology · Mathematics 2026-03-30 Marc Kegel , Isacco Nonino

We investigate commensurability classes of hyperbolic knot complements in the generic case of knots without hidden symmetries. We show that such knot complements which are commensurable are cyclically commensurable, and that there are at…

Geometric Topology · Mathematics 2014-11-11 Michel Boileau , Steven Boyer , Radu Cebanu , Genevieve S. Walsh

In this paper we give necessary and sufficient conditions for a knot type to admit non-loose Legendrian and transverse representatives in some overtwisted contact structure, classify all non-loose rational unknots in lens spaces, and…

Geometric Topology · Mathematics 2023-10-10 Rima Chatterjee , John B. Etnyre , Hyunki Min , Anubhav Mukherjee

For some families of two-bridge knots, including double-twist knots with genus at least four, we determine precisely the set of integers $n>1$ such that the fundamental group of the $n$-fold cyclic branched cover of the 3-sphere along these…

Geometric Topology · Mathematics 2020-02-26 Hannah Turner

We say a knot $k$ in the 3-sphere $\mathbb S^3$ has {\it Property $IE$} if the infinite cyclic cover of the knot exterior embeds into $\mathbb S^3$. Clearly all fibred knots have Property $IE$. There are infinitely many non-fibred knots…

Geometric Topology · Mathematics 2007-05-23 Boju Jiang , Yi Ni , Shicheng Wang , Qing Zhou

Neuwirth asked if any non-trivial knot in the 3-sphere can be embedded in a closed surface so that the complement of the surface is a connected essential surface for the knot complement. In this paper, we examine some variations on this…

Geometric Topology · Mathematics 2011-03-15 Makoto Ozawa , J. Hyam Rubinstein

We present explicit infinite families of twisted torus knots that are not fibered. Our approach relies on an explicit formula for the Alexander polynomial derived in our previous work. We show that the leading coefficients of the Alexander…

Geometric Topology · Mathematics 2026-03-09 Adnan , Kyungbae Park

The main result of this paper is a negative answer to the question: are all transversal knot types transversally simple? An explicit infinite family of examples is given of closed 3-braids that define transversal knot types that are not…

Geometric Topology · Mathematics 2009-03-02 Joan S Birman , William W Menasco

We observe that most known results of the form "v is not a finite-type invariant" follow from two basic theorems. Among those invariants which are not of finite type, we discuss examples which are "ft-independent" and examples which are…

Geometric Topology · Mathematics 2007-05-23 Theodore Stanford , Rolland Trapp
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