English

Zeros distribution of gaussian entire functions

Complex Variables 2014-01-14 v1

Abstract

In this paper we consider a random entire function of the form f(z,ω)=n=0+ξn(ω)anzn,f(z,\omega )=\sum\nolimits_{n=0}^{+\infty}\xi_n(\omega )a_nz^n, where ξn(ω)\xi_n(\omega ) are independent standard\break complex gaussian random variables and anCa_n\in\mathbb{C} satisfy the relations\break limn+ann=0\varlimsup\limits_{n\to+\infty}\sqrt[n]{|a_n|}=0 and #{n ⁣:an0}=+. \#\{n\colon a_n\neq0\}=+\infty. We investigate asymptotic properties of the probability P0(r)=P{ω ⁣:f(z,ω)P_0(r)=P\{\omega\colon f(z,\omega ) has no zeros inside rD}.r\mathbb{D}\}. Denote p0(r)=lnP0(r), N(r)=#{n ⁣:ln(anrn)>0}, p_0(r)=\ln^-P_0(r),\ N(r)=\#\{n\colon \ln (|a_n|r^n)>0\}, s(r)=n=0+ln+(anrn). s(r)=\sum_{n=0}^{+\infty}\ln^+(|a_n|r^{n}). Assuming that a00a_0\neq0 we prove that 0limr+, rEln(p0(r)s(r))lns(r), limr+, rEln(p0(r)s(r))lns(r)12, 0\leq\varliminf_{r\to+\infty,\ r\notin E}\frac{\ln(p_0(r)- s(r))}{\ln s(r)},\ \varlimsup_{r\to+\infty,\ r\notin E}\frac{\ln(p_0(r)- s(r))}{\ln s(r)}\leq\frac12, limr+, rEln(p0(r)s(r))lnN(r)=1. \lim\limits_{r\to+\infty,\ r\notin E}\frac{\ln(p_0(r)- s(r))}{\ln N(r)}=1. where EE is a set of finite logarithmic measure. Remark that the previous inequalities are sharp. Also we give an answer to open question from \cite[p. 119]{nishry 5}.

Keywords

Cite

@article{arxiv.1401.2776,
  title  = {Zeros distribution of gaussian entire functions},
  author = {A. O. Kuryliak and O. B. Skaskiv},
  journal= {arXiv preprint arXiv:1401.2776},
  year   = {2014}
}