English

Where is $f(z)/f'(z)$ univalent?

Complex Variables 2015-03-18 v1

Abstract

Let S{\mathcal S} denote the family of all univalent functions ff in the unit disk \ID\ID with the normalization f(0)=0=f(0)1f(0)=0= f'(0)-1. There is an intimate relationship between the operator Pf(z)=f(z)/f(z)P_f(z)=f(z)/f'(z) and the Danikas-Ruscheweyh operator Tf:=0z(tf(t)/f(t))dtT_f:=\int_{0}^{z}(tf'(t)/f(t))\,dt. In this paper we mainly consider the univalence problem of F=PfF=P_f, where ff belongs to some subclasses of S{\mathcal S}. Among several sharp results and non-sharp results, we also show that if fSf\in {\mathcal S}, then FUF \in {\mathcal U} in the disk z<r|z|<r with rr60.360794r\leq r_6\approx 0.360794 and conjecture that the upper bound for such rr is 21\sqrt{2}-1.

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Cite

@article{arxiv.1503.04931,
  title  = {Where is $f(z)/f'(z)$ univalent?},
  author = {Milutin Obradović and Saminathan Ponnusamy and Karl-Joachim Wirths},
  journal= {arXiv preprint arXiv:1503.04931},
  year   = {2015}
}

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11 pages