English

When the law of large numbers fails for increasing subsequences of random permutations

Probability 2009-09-29 v3 Combinatorics

Abstract

Let the random variable Zn,kZ_{n,k} denote the number of increasing subsequences of length kk in a random permutation from SnS_n, the symmetric group of permutations of {1,...,n}\{1,...,n\}. In a recent paper [Random Structures Algorithms 29 (2006) 277--295] we showed that the weak law of large numbers holds for Zn,knZ_{n,k_n} if kn=o(n2/5)k_n=o(n^{2/5}); that is, limnZn,knEZn,kn=1inprobability.\lim_{n\to\infty}\frac{Z_{n,k_n}}{EZ_{n,k_n}}=1\qquad in probability. The method of proof employed there used the second moment method and demonstrated that this method cannot work if the condition kn=o(n2/5)k_n=o(n^{2/5}) does not hold. It follows from results concerning the longest increasing subsequence of a random permutation that the law of large numbers cannot hold for Zn,knZ_{n,k_n} if kncn1/2k_n\ge cn^{1/2}, with c>2c>2. Presumably there is a critical exponent l0l_0 such that the law of large numbers holds if kn=O(nl)k_n=O(n^l), with l<l0l<l_0, and does not hold if lim supnknnl>0\limsup_{n\to\infty}\frac{k_n}{n^l}>0, for some l>l0l>l_0. Several phase transitions concerning increasing subsequences occur at l=1/2l=1/2, and these would suggest that l0=1/2l_0={1/2}. However, in this paper, we show that the law of large numbers fails for Zn,knZ_{n,k_n} if lim supnknn4/9=\limsup_{n\to\infty}\frac{k_n}{n^{4/9}}=\infty. Thus, the critical exponent, if it exists, must satisfy l0[2/5,4/9]l_0\in[{2/5},{4/9}].

Keywords

Cite

@article{arxiv.math/0604067,
  title  = {When the law of large numbers fails for increasing subsequences of random permutations},
  author = {Ross G. Pinsky},
  journal= {arXiv preprint arXiv:math/0604067},
  year   = {2009}
}

Comments

Published at http://dx.doi.org/10.1214/009117906000000728 in the Annals of Probability (http://www.imstat.org/aop/) by the Institute of Mathematical Statistics (http://www.imstat.org)