What does it mean to have a quantum gravitational theory of de Sitter Space?
Abstract
We argue that if de Sitter space is indeed represented by a finite dimensional quantum system, then semi-classical considerations, combined with the fundamental principles of quantum measurement theory, imply that any theoretical model of it is ambiguous. If our own universe asymptotes to such a de Sitter state, and if a model of it as a finite system can be embedded in a sequence of models that converges to a non-perturbative completion of a unique superstring model in asymptotically flat space, then one might be able to find a very precise mathematical model of our universe. However, even the most comprehensive experiments possible to local detectors in the universe cannot measure more than a tiny fraction of the total number of q-bits in the system.
Keywords
Cite
@article{arxiv.2605.13490,
title = {What does it mean to have a quantum gravitational theory of de Sitter Space?},
author = {Tom Banks},
journal= {arXiv preprint arXiv:2605.13490},
year = {2026}
}
Comments
LaTeX, 6 pages