English

Unbounded convex polyhedra as polynomial images of Euclidean spaces

Algebraic Geometry 2024-01-24 v1

Abstract

In a previous work we proved that each nn-dimensional convex polyhedron KsubsetRn{\mathcal K}subset{\mathbb R}^n and its relative interior are regular images of Rn{\mathbb R}^n. As the image of a non-constant polynomial map is an unbounded semialgebraic set, it is not possible to substitute regular maps by polynomial maps in the previous statement. In this work we determine constructively all unbounded nn-dimensional convex polyhedra KRn{\mathcal K}\subset{\mathbb R}^n that are polynomial images of Rn{\mathbb R}^n. We also analyze for which of them the interior Int(K){\rm Int}({\mathcal K}) is a polynomial image of Rn{\mathbb R}^n. A discriminating object is the recession cone C(K)\vec{\mathcal C}({\mathcal K}) of K{\mathcal K}. Namely, \em K{\mathcal K} is a polynomial image of Rn{\mathbb R}^n if and only if C(K)\vec{{\mathcal C}}({\mathcal K}) has dimension nn\em. In addition, \em Int(K){\rm Int}({\mathcal K}) is a polynomial image of Rn{\mathbb R}^n if and only if C(K)\vec{{\mathcal C}}({\mathcal K}) has dimension nn and K{\mathcal K} has no bounded faces of dimension n1n-1\em. A key result is an improvement of Pecker's elimination of inequalities to represent semialgebraic sets as projections of algebraic sets. Empirical approaches suggest us that there are `few' polynomial maps that have a concrete convex polyhedron as a polynomial image and that there are even fewer for which it is affordable to show that their images actually correspond to our given convex polyhedron. This search of a `needle in the haystack' justifies somehow the technicalities involved in our constructive proofs.

Keywords

Cite

@article{arxiv.2401.12558,
  title  = {Unbounded convex polyhedra as polynomial images of Euclidean spaces},
  author = {José F. Fernando and J. M. Gamboa and Carlos Ueno},
  journal= {arXiv preprint arXiv:2401.12558},
  year   = {2024}
}

Comments

40 pages, 13 figures