English

Two Body Hadronic Decays $\Lambda_{b}(\frac{1}{2}^{+})\rightarrow B^{\ast}(\frac{3}{2}^{+})+P$ in a quark model

High Energy Physics - Phenomenology 2017-04-24 v1

Abstract

The framework under which decays Λb(12+)B(12+)+M\Lambda_{b}(\frac{1}{2}^{+})\rightarrow B(\frac{1}{2}^{+})+M are analyzed is not applicable for the decays Λb(12+)B(32+)+M\Lambda_{b}(\frac{1}{2}^{+})\rightarrow B^{\ast}(\frac{3}{2} ^{+})+M. These decays occur through a baryon pole Σc0\Sigma^{0}_{c} which is generated by the W-exchange diagram in the process b+uWc+db+u \xrightarrow {W} c+d. The effective Hamiltonian which arises from the W-exchange diagram is expressed in the non relativistic limit. Since % \Sigma^{0}_{c} belongs to representation 66 of SU(3), it contributes to two sets of decays: ΛbΔ0D0,ΔD+,\Lambda_{b}\rightarrow\Delta^{0}D^{0},\Delta^{-}D^{+},% \Sigma^{*-}D_s^{+} and ΛbΣcπ+,\Lambda_{b}\rightarrow\Sigma^{\ast-}_{c}\pi^{+},% \Sigma^{\ast 0}_{c}\pi^{0}\;, \Xi^{\ast 0}_{c}K^{0}. The branching ratios for these decays are evaluated which can be compared with their experimental values when the data become available. Other prediction of the model is that asymmetry parameter α=0\alpha = 0, since baryon pole contributes to parity conserving (p-wave) amplitude and does not contribute to parity violating (d-wave) amplitude.

Keywords

Cite

@article{arxiv.1704.06480,
  title  = {Two Body Hadronic Decays $\Lambda_{b}(\frac{1}{2}^{+})\rightarrow B^{\ast}(\frac{3}{2}^{+})+P$ in a quark model},
  author = {Fayyazuddin},
  journal= {arXiv preprint arXiv:1704.06480},
  year   = {2017}
}

Comments

No Figure, 10 pages, A version that appeared in the Physics Review D