Twisted Alexander polynomials and surjectivity of a group homomorphism
Geometric Topology
2014-10-01 v1 Group Theory
Abstract
If phi: G-->G' is a surjective homomorphism, we prove that the twisted Alexander polynomial of G is divisible by the twisted Alexander polynomial of G'. As an application, we show non-existence of surjective homomorphism between certain knot groups.
Cite
@article{arxiv.math/0510224,
title = {Twisted Alexander polynomials and surjectivity of a group homomorphism},
author = {Teruaki Kitano and Masaaki Suzuki and Masaaki Wada},
journal= {arXiv preprint arXiv:math/0510224},
year = {2014}
}
Comments
Published by Algebraic and Geometric Topology at http://www.maths.warwick.ac.uk/agt/AGTVol5/agt-5-51.abs.html