English

Toward a Three-dimensional Counterpart of Cruse's Theorem

Combinatorics 2025-09-16 v2

Abstract

Completing partial latin squares is NP-complete. Motivated by Ryser's theorem for latin rectangles, in 1974, Cruse found conditions that ensure a partial symmetric latin square of order mm can be embedded in a symmetric latin square of order nn. Loosely speaking, this results asserts that an nn-coloring of the edges of the complete mm-vertex graph KmK_m can be embedded in a one-factorization of KnK_n if and only if nn is even and the number of edges of each color is at least mn/2m-n/2. We establish necessary and sufficient conditions under which an edge-coloring of the complete λ\lambda-fold mm-vertex 3-graph λKm3\lambda K_m^3 can be embedded in a one-factorization of λKn3\lambda K_n^3. In particular, we prove the first known Ryser type theorem for hypergraphs by showing that if n0  (mod  3)n \equiv 0 \;(\bmod\; 3), any edge-coloring of λKm3\lambda K_m^3 where the number of triples of each color is at least m/2n/6m/2-n/6, can be embedded in a one-factorization of λKn3\lambda K_n^3. Finally we prove an Evans type result by showing that if n0  (mod  3)n \equiv 0 \;(\bmod\; 3) and n3mn\geq 3m, then any qq-coloring of the edges of any FλKm3F\subseteq\lambda K_m^3 can be embedded in a one-factorization of λKn3\lambda K_n^3 as long as qλ(n12)λ(m3)/m/3q\leq \lambda \binom{n-1}{2}-\lambda \binom{m}{3}/\left\lfloor m/3 \right\rfloor.

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Cite

@article{arxiv.2209.09100,
  title  = {Toward a Three-dimensional Counterpart of Cruse's Theorem},
  author = {Amin Bahmanian},
  journal= {arXiv preprint arXiv:2209.09100},
  year   = {2025}
}

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12 pages