Token Jumping in Planar Graphs has Linear Sized Kernels
Abstract
Let be a planar graph and and be two independent sets in , each of size . We begin with a "token" on each vertex of and seek to move all tokens to , by repeated "token jumping", removing a single token from one vertex and placing it on another vertex. We require that each intermediate arrangement of tokens again specifies an independent set of size . Given , , and , we ask whether there exists a sequence of token jumps that transforms to . When is part of the input, this problem is known to be PSPACE-complete. However, it was shown by Ito, Kami\'nski, and Ono to be fixed-parameter tractable. That is, when is fixed, the problem can be solved in time polynomial in the order of . Here we strengthen the upper bound on the running time in terms of by showing that the problem has a kernel of size linear in . More precisely, we transform an arbitrary input problem on a planar graph into an equivalent problem on a (planar) graph with order .
Cite
@article{arxiv.2401.09543,
title = {Token Jumping in Planar Graphs has Linear Sized Kernels},
author = {Daniel W. Cranston},
journal= {arXiv preprint arXiv:2401.09543},
year = {2024}
}
Comments
There is an error in the proof of Claim 7. This general approach can be salvaged to give a kernel that is quadratic in k (rather than linear). This has been done, with two coauthors, in the more general context of graphs on arbitrary surfaces in arXiv:2408.04743 [cs.DS]