There is a $+$-Ramsey \textsf{MAD} family
Logic
2018-10-23 v1
Abstract
We answer an old question of Michael Hru\v{s}\'{a}k by constructing a -Ramsey \textsf{MAD} family without the need of any additional axioms beyond We also prove that every Miller-indestructible \textsf{MAD }family is -Ramsey, this improves a result of Michael Hru\v{s}\'{a}k.
Cite
@article{arxiv.1810.08763,
title = {There is a $+$-Ramsey \textsf{MAD} family},
author = {Osvaldo Guzman},
journal= {arXiv preprint arXiv:1810.08763},
year = {2018}
}