The $r$th moment of the divisor function: an elementary approach

Let $\tau(n)$ be the number of divisors of $n$. We give an elementary proof of the fact that $$\sum_{n\le x} \tau(n)^r =xC_{r} (\log x)^{2^r-1}+O(x(\log x)^{2^r-2}),$$ for any integer $r\ge 2$. Here, $$C_{r}=\frac{1}{(2^r-1)!} \prod_{p\ge 2}\left( \left(1-\frac{1}{p}\right)^{2^r} \left(\sum_{\alpha\ge 0} \frac{(\alpha+1)^r}{p^{\alpha}}\right)\right).$$