English

The probability of entanglement

Operator Algebras 2009-11-13 v2 Quantum Physics

Abstract

We show that states on tensor products of matrix algebras whose ranks are relatively small are {\em almost surely} entangled, but that states of maximum rank are not. More precisely, let M=Mm(C)M=M_m(\mathbb C) and N=Mn(C)N=M_n(\mathbb C) be full matrix algebras with mnm\geq n, fix an arbitrary state ω\omega of NN, and let E(ω)E(\omega) be the set of all states of MNM\otimes N that extend ω\omega. The space E(ω)E(\omega) contains states of rank rr for every r=1,2,...,m\rankωr=1,2,...,m\cdot\rank\omega, and it has a filtration into compact subspaces E1(ω)E2(ω)...Em\rankω=E(ω), E^1(\omega)\subseteq E^2(\omega)\subseteq ...\subseteq E^{m\cdot\rank\omega}=E(\omega), where Er(ω)E^r(\omega) is the set of all states of E(ω)E(\omega) having rank r\leq r. We show first that for every rr, there is a real-analytic manifold VrV^r, homogeneous under a transitive action of a compact group GrG^r, which parameterizes Er(ω)E^r(\omega). The unique GrG^r-invariant probability measure on VrV^r promotes to a probability measure Pr,ωP^{r,\omega} on Er(ω)E^r(\omega), and Pr,ωP^{r,\omega} assigns probability 1 to states of rank rr. The resulting probability space (Er(ω),Pr,ω)(E^r(\omega),P^{r,\omega}) represents ``choosing a rank rr extension of ω\omega at random". Main result: For every r=1,2,...,[\rankω/2]r=1,2,...,[\rank \omega/2], states of (Er(ω),Pr,ω)(E^r(\omega),P^{r,\omega}) are almost surely entangled.

Keywords

Cite

@article{arxiv.0712.4163,
  title  = {The probability of entanglement},
  author = {William Arveson},
  journal= {arXiv preprint arXiv:0712.4163},
  year   = {2009}
}

Comments

Significant revisions and clarifications, more references. 33 pages

R2 v1 2026-06-21T09:57:40.674Z