English

Symmetric polynomials and non-finitely generated $Sym (\mathbb N)$-invariant ideals

Rings and Algebras 2015-09-30 v1

Abstract

Let KK be a field and let N={1,2,}\mathbb N = \{1,2, \dots \}. Let Rn=K[xij1in,jN]R_n=K[x_{ij} \mid 1\le i\le n, j\in \mathbb N] be the ring of polynomials in xijx_{ij} (1in,jN)(1 \le i \le n, j \in \mathbb N) over KK. Let Sn=Sym({1,2,,n})S_n = Sym (\{1,2, \ldots, n \}) and Sym(N)Sym (\mathbb N) be the groups of the permutations of the sets {1,2,,n}\{1,2,\dots, n \} and N\mathbb N, respectively. Then SnS_n and Sym(N)Sym (\mathbb N) act on RnR_n in a natural way: τ(xij)=xτ(i)j\tau (x_{ij})=x_{\tau(i)j} and σ(xij)=xiσ(j)\sigma (x_{ij})=x_{i\sigma (j)} for all τSn\tau \in S_n and σSym(N)\sigma \in Sym(\mathbb N). Let Rn\overline{R}_n be the subalgebra of the symmetric polynomials in RnR_n, Rn={fRnτ(f)=f\mboxforeachτSn}. \overline{R}_n = \{f \in R_n \mid \tau (f) = f \mbox{for each} \tau \in S_n \} . In 1992 the second author proved that if char(K)=0char (K)= 0 or char(K)=p>nchar(K)=p > n then every Sym(N)Sym (\mathbb N)-invariant ideal in Rn\overline{R}_n is finitely generated (as such). In this note we prove that this is not the case if char(K)=pnchar (K)=p\le n. We also survey some results about Sym(N)Sym (\mathbb N)-invariant ideals in polynomial algebras and some related results.

Keywords

Cite

@article{arxiv.1310.7608,
  title  = {Symmetric polynomials and non-finitely generated $Sym (\mathbb N)$-invariant ideals},
  author = {Eudes Antonio da Costa and Alexei Krasilnikov},
  journal= {arXiv preprint arXiv:1310.7608},
  year   = {2015}
}

Comments

8 pages

R2 v1 2026-06-22T01:55:58.129Z