English

Spaceability of sets of nowhere $L^q$ functions

Functional Analysis 2011-10-27 v1

Abstract

We say that a function f:[0,1]Rf:[0,1]\rightarrow \R is \emph{nowhere LqL^q} if, for each nonvoid open subset UU of [0,1][0,1], the restriction fUf|_U is not in Lq(U)L^q(U). For a fixed 1p<1 \leq p <\infty, we will show that the set S_p\doteq {f \in L^p[0,1]: f is nowhere $L^q$, for each p<q \leq \infty}, united with 0{0}, contains an isometric and complemented copy of p\ell_p. In particular, this improves a result from G. Botelho, V. F\'avaro, D. Pellegrino, and J. B. Seoane-Sep\'ulveda, Lp[0,1]q>pLq[0,1]L_p[0,1]\setminus \cup_{q>p} L_q[0,1] is spaceable for every p>0p>0, preprint, 2011., since SpS_p turns out to be spaceable. In addition, our result is a generalization of one of the main results from S. G{\l}\c{a}b, P. L. Kaufmann, and L. Pellegrini, Spaceability and algebrability of sets of nowhere integrable functions, preprint, 2011.

Keywords

Cite

@article{arxiv.1110.5774,
  title  = {Spaceability of sets of nowhere $L^q$ functions},
  author = {Pedro L. Kaufmann and Leonardo Pellegrini},
  journal= {arXiv preprint arXiv:1110.5774},
  year   = {2011}
}