English

Slice rank and partition rank of the determinant

Combinatorics 2025-09-09 v1 Computational Complexity

Abstract

The Laplace expansion expresses the n×nn \times n determinant detn\det_n as a sum of nn products. Do shorter expansions exist? In this paper we: - Fully determine the slice rank decompositions of detn\det_n (where each product must contain a linear factor): In this case, we show that nn summands are necessary, and moreover, the only such expansions with nn summands are equivalent (in a precise sense) to the Laplace expansion. - Prove a logarithmic lower bound for the partition rank of detn\det_n (where each product is of multilinear forms): In this case, we show that at least log2(n)+1\log_2(n)+1 summands are needed. We also explain why existing techniques fail to yield any nontrivial lower bound, and why our new method cannot give a super-logarithmic lower bound. - Separate partition rank from slice rank for detn\det_n: we find a quadratic expansion for det4\det_4, over any field, with fewer summands than the Laplace expansion. This construction is related to a well-known example of Green-Tao and Lovett-Meshulam-Samorodnitsky disproving the naive version of the Gowers Inverse conjecture over small fields. An important motivation for these questions comes from the challenge of separating structure and randomness for tensors. On the one hand, we show that the random construction fails to separate: for a random tensor of partition rank rr, the analytic rank is ro(1)r-o(1) with high probability. On the other hand, our results imply that the determinant yields the first asymptotic separation between partition rank and analytic rank of dd-tensors, with their ratio tending to infinity with dd.

Keywords

Cite

@article{arxiv.2509.06294,
  title  = {Slice rank and partition rank of the determinant},
  author = {Amichai Lampert and Guy Moshkovitz},
  journal= {arXiv preprint arXiv:2509.06294},
  year   = {2025}
}