Simultaneous ping-pong for finite subgroups of reductive groups
Abstract
Let be a Zariski-dense subgroup of a reductive group defined over a field . Given a finite collection of finite subgroups () of avoiding the center, we establish a criterion to ensure that the set of elements of that form a free product with every (the so-called simultaneous ping-pong partners for ) is both Zariski- and profinitely dense in . This criterion applies namely to direct products of inner -forms of , and gives a positive answer to this particular case of a question asked by Bekka, Cowling and de la Harpe. For torsion elements, a complication arises due to the fact that a finite cyclic group can split into a direct product. When is the multiplicative group of a semisimple algebra, we also give a more explicit method to obtain free products between two given finite subgroups, via first-order deformations. In the second half, we investigate the case where is the multiplicative group of the group algebra of a finite group , and is the group of units of an order in . In this regard, we prove that the set of bicylic units that play ping-pong with a given shifted bicyclic unit, is Zariski- and profinitely dense, addressing a long-standing belief in the field of group rings. This result is deduced from the criterion above, combined with sharp existence results for well-behaved irreducible representations of that are center-preserving on a given subgroup.
Cite
@article{arxiv.2510.23957,
title = {Simultaneous ping-pong for finite subgroups of reductive groups},
author = {Geoffrey Janssens and Doryan Temmerman and François Thilmany},
journal= {arXiv preprint arXiv:2510.23957},
year = {2025}
}
Comments
51 pages. Comments are welcome