English

Sign Laws and Mock Theta Functions

Number Theory 2026-06-30 v1

Abstract

Let ρ(q)=m0q2m(m+1)(1+q+q2)(1+q3+q6)(1+q2m+1+q4m+2)=n0r(n)qn \rho(q)=\sum_{m\geq 0}\frac{q^{2m(m+1)}}{(1+q+q^2)(1+q^3+q^6)\cdots(1+q^{2m+1}+q^{4m+2})} =\sum_{n\geq 0}r(n)q^n be Ramanujan's third order mock theta function. We prove the sign law r(3m)>0,r(3m+1)0,r(3m+2)0, r(3m)>0,\qquad r(3m+1)\leq 0,\qquad r(3m+2)\leq 0, with equality precisely at n=2,4,8,11,20n=2,4,8,11,20. Watson's identity 2ρ(q)+ω(q)=T(q) 2\rho(q)+\omega(q)=T(q) reduces the problem to comparing the mock theta function ω(q)\omega(q) with the eta quotient T(q)=3(q6;q6)4(q3;q3)2(q2;q2). T(q)=3\frac{(q^6;q^6)_\infty^4}{(q^3;q^3)_\infty^2(q^2;q^2)_\infty}. We prove effective root-of-unity estimates for this difference. The polar contributions at q=1q=1 cancel, the contribution at q=1q=-1 is polynomially bounded, and the first surviving exponential term occurs at the primitive cubic roots of unity. It has the sign pattern κ0=13cosπ18>0,κ1=13sin2π9<0,κ2=13sinπ9<0. \kappa_0=\frac13\cos\frac\pi{18}>0,\qquad \kappa_1=-\frac13\sin\frac{2\pi}{9}<0, \qquad \kappa_2=-\frac13\sin\frac\pi9<0. The resulting effective asymptotic proves the desired sign law for all sufficiently large nn, and an exact integer-arithmetic verification completes the finite range. We conclude by indicating how the same root-of-unity method should lead to analogous sign laws for other third order mock theta functions, including ϕ(q)\phi(q) and χ(q)\chi(q).

Cite

@article{arxiv.2606.31606,
  title  = {Sign Laws and Mock Theta Functions},
  author = {Manosij Ghosh Dastidar},
  journal= {arXiv preprint arXiv:2606.31606},
  year   = {2026}
}
R2 v1 2026-07-22T20:17:34.476Z