Rigidity of $4$-dimensional complete self-shrinkers in $\mathbb{R}^{5}$
Differential Geometry
2022-12-08 v2
Abstract
We show that any -dimensional complete self-shrinker in with constant squared norm of the second fundamental form, and constant is isometric to , where are components of the second fundamental form, , and . As an application, we obtain a classification result.
Keywords
Cite
@article{arxiv.2209.07955,
title = {Rigidity of $4$-dimensional complete self-shrinkers in $\mathbb{R}^{5}$},
author = {Chengyang Yi},
journal= {arXiv preprint arXiv:2209.07955},
year = {2022}
}
Comments
18 pages. We corrected some mistakes in section 3 of the previous version