English

Rational vs transcendental points on analytic Riemann surfaces

Algebraic Geometry 2018-08-30 v2 Number Theory

Abstract

Let (X,L)(X,L) be a polarized variety over a number field. We suppose that LL is an hermitian line bundle. Let MM be a non compact Riemann Surface and UMU\subset M be a relatively compact open set. Let φ:MX(C)\varphi:M\to X({\Bbb C}) be a holomorphic map. For every positive real number TT, let AU(T)A_U(T) be the cardinality of the set of zUz\in U such that φ(z)X(K)\varphi (z)\in X(K) and hL(φ(z))Th_L(\varphi(z))\leq T. After a revisitation of the proof of the sub exponential bound for AU(T)A_U(T), obtained by Bombieri and Pila , we show that there are intervals of TT's as big as we want for which AU(T)A_U(T) is upper bounded by a polynomial in TT. We then introduce subsets of type SS with respect of φ\varphi. These are compact subsets of MM for which an inequality similar to Liouville inequality on algebraic points holds. We show that, if MM contains a subset of type SS, then, {\it for every value of TT} the number AU(T)A_U(T) is bounded by a polynomial in TT. As a consequence, we show that if MM is a smooth leaf of a foliation in curves then AU(T)A_U(T) is bounded by a polynomial in TT. Let S(X)S(X) be the subset (full for the Lebesgue measure) of points which verify some kind of Liouville inequalities. In the second part we prove that φ1(S(X))\varphi^{-1}(S(X))\neq\emptyset if and only if φ1(S(X))\varphi^{-1}(S(X)) is full for the Lebesgue measure on MM.

Keywords

Cite

@article{arxiv.1806.10844,
  title  = {Rational vs transcendental points on analytic Riemann surfaces},
  author = {Carlo Gasbarri},
  journal= {arXiv preprint arXiv:1806.10844},
  year   = {2018}
}

Comments

First version, comments are welcome

R2 v1 2026-06-23T02:44:32.511Z