English

Radio Number for the Cartesian Product of Two Trees

Combinatorics 2022-03-01 v1 Discrete Mathematics

Abstract

Let GG be a simple connected graph. For any two vertices uu and vv, let d(u,v)d(u,v) denote the distance between uu and vv in GG, and let diam(G)diam(G) denote the diameter of GG. A radio-labeling of GG is a function ff which assigns to each vertex a non-negative integer (label) such that for every distinct vertices uu and vv in GG, it holds that f(u)f(v)diam(G)d(u,v)+1|f(u)-f(v)| \geq diam(G) - d(u,v) +1. The span of ff is the difference between the largest and smallest labels of f(V)f(V). The radio number of GG, denoted by rn(G)rn(G), is the smallest span of a radio labeling admitted by GG. In this paper, we give a lower bound for the radio number of the Cartesian product of two trees. Moreover, we present three necessary and sufficient conditions, and three sufficient conditions for the product of two trees to achieve this bound. Applying these results, we determine the radio number of the Cartesian product of two stars as well as a path and a star.

Keywords

Cite

@article{arxiv.2202.13983,
  title  = {Radio Number for the Cartesian Product of Two Trees},
  author = {Devsi Bantva and Daphne Der-Fen Liu},
  journal= {arXiv preprint arXiv:2202.13983},
  year   = {2022}
}

Comments

17 pages, 5 figures