English

Quotient groups of IA-automorphisms of free metabelian groups

Group Theory 2020-12-29 v2

Abstract

For a positive integer nn, with n2n \geq 2, let MnM_n be a free metabelian group of rank nn. For cNc \in \mathbb{N}, let γc(Mn)\gamma_c(M_n) be the cc-th term of the lower central series of MnM_n. For c2c \geq 2, let IcA(Mn){\rm I}_{c}{\rm A}(M_n) be the subgroup of Aut(Mn){\rm Aut}(M_{n}) consisting of all automorphisms inducing the identity mapping on Mn/γc(Mn)M_n/\gamma_c(M_n). In this paper, we study the quotient groups Lc(IA(Mn))=IcA(Mn)/Ic+1A(Mn){\cal L}^{c}({\rm IA}(M_{n})) = {\rm I}_{c}{\rm A}(M_n)/{\rm I}_{c+1}{\rm A}(M_n) for all nn and cc. For c2c \geq 2, we show γc(IA(M2))=Ic+1A(M2))\gamma_{c}({\rm IA}(M_{2})) = {\rm I}_{c+1}{\rm A}(M_{2})). For n=3n = 3, we show γ3(IA(M3))I4A(M3)\gamma_{3}({\rm IA}(M_{3})) \neq {\rm I}_{4}{\rm A}(M_{3}) and so, the Andreadakis' conjecture (for a free metabelian group) is not valid for n=3n = 3 and c=3c = 3. For n4n \geq 4 and c3c \geq 3, we prove that Lc(IA(Mn))=γc1(IA(Mn))Ic+1A(Mn)/Ic+1A(Mn){\cal L}^{c}({\rm IA}(M_{n})) = \gamma_{c-1}({\rm IA}(M_{n})){\rm I}_{c+1}{\rm A}(M_{n})/{\rm I}_{c+1}{\rm A}(M_{n}).

Keywords

Cite

@article{arxiv.2012.13286,
  title  = {Quotient groups of IA-automorphisms of free metabelian groups},
  author = {C. E. Kofinas and A. I. Papistas},
  journal= {arXiv preprint arXiv:2012.13286},
  year   = {2020}
}