English

Quadratic and cubic invariants of unipotent affine automorphisms

Rings and Algebras 2007-05-23 v1 Algebraic Geometry

Abstract

Let KK be an arbitrary field of characteristic zero, Pn:=K[x1,...,xn]P_n:= K[ x_1, ..., x_n] be a polynomial algebra, and Pn,x1:=K[x11,x1,...,xn]P_{n, x_1}:= K[x_1^{-1}, x_1, ..., x_n], for n2n\geq 2. Let \sAutK(Pn)\s' \in {\rm Aut}_K(P_n) be given by x1x11,x1x2+x1,...,xnxn+xn1. x_1\mapsto x_1-1, \quad x_1\mapsto x_2+x_1,\quad ... ,\quad x_n\mapsto x_n+x_{n-1}. It is proved that the algebra of invariants, Fn:=Pn\sF_n':= P_n^{\s'}, is a polynomial algebra in n1n-1 variables which is generated by [n2][\frac{n}{2}] quadratic and [n12][\frac{n-1}{2}] cubic (free) generators that are given explicitly. Let \sAutK(Pn)\s \in {\rm Aut}_K(P_n) be given by %\sAutK(Pn):\s \in {\rm Aut}_K(P_n): x_1\mapsto x_1, \quad x_1\mapsto x_2+x_1, \quad ... ,\quad x_n\mapsto x_n+x_{n-1}. It is well-known that the algebra of invariants, Fn:=Pn\sF_n:= P_n^\s, is finitely generated (Theorem of Weitzenb\"ock, \cite{Weitz}, 1932), has transcendence degree n1n-1, and that one can give an explicit transcendence basis in which the elements have degrees 1,2,3,...,n11, 2, 3, ..., n-1. However, it is an old open problem to find explicit generators for FnF_n. We find an explicit vector space basis for the quadratic invariants, and prove that the algebra of invariants Pn,x1\sP_{n, x_1}^\s is a polynomial algebra over K[x1,x11]K[x_1, x_1^{-1}] in n2n-2 variables which is generated by [n12][\frac{n-1}{2}] quadratic and [n22][\frac{n-2}{2}] cubic (free) generators that are given explicitly. The coefficients of these quadratic and cubic invariants throw light on the `unpredictable combinatorics' of invariants of affine automorphisms and of SL2SL_2-invariants.

Keywords

Cite

@article{arxiv.math/0606196,
  title  = {Quadratic and cubic invariants of unipotent affine automorphisms},
  author = {V V Bavula and T H Lenagan},
  journal= {arXiv preprint arXiv:math/0606196},
  year   = {2007}
}

Comments

29 pages