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Powerfree sums of proper divisors

Number Theory 2021-06-30 v1

Abstract

Let s(n):=dn, d<nds(n):= \sum_{d\mid n,~d<n} d denote the sum of the proper divisors of nn. It is natural to conjecture that for each integer k2k\ge 2, the equivalence n is kth powerfrees(n) is kth powerfree \text{$n$ is $k$th powerfree} \Longleftrightarrow \text{$s(n)$ is $k$th powerfree} holds almost always (meaning, on a set of asymptotic density 11). We prove this for k4k\ge 4.

Keywords

Cite

@article{arxiv.2106.14953,
  title  = {Powerfree sums of proper divisors},
  author = {Paul Pollack and Akash Singha Roy},
  journal= {arXiv preprint arXiv:2106.14953},
  year   = {2021}
}

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7 pages