English

Operators which are polynomially isometric to a normal operator

Functional Analysis 2019-08-22 v2

Abstract

Let H\mathcal{H} be a complex, separable Hilbert space and B(H)\mathcal{B}(\mathcal{H}) denote the algebra of all bounded linear operators acting on H\mathcal{H}. Given a unitarily-invariant norm u\| \cdot \|_u on B(H)\mathcal{B}(\mathcal{H}) and two linear operators AA and BB in B(H)\mathcal{B}(\mathcal{H}), we shall say that AA and BB are \emph{polynomially isometric relative to} u\| \cdot \|_u if p(A)u=p(B)u\| p(A) \|_u = \| p(B) \|_u for all polynomials pp. In this paper, we examine to what extent an operator AA being polynomially isometric to a normal operator NN implies that AA is itself normal. More explicitly, we first show that if u\| \cdot \|_u is any unitarily-invariant norm on Mn(C)\mathbb{M}_n(\mathbb{C}), if A,NMn(C)A, N \in \mathbb{M}_n(\mathbb{C}) are polynomially isometric and NN is normal, then AA is normal. We then extend this result to the infinite-dimensional setting by showing that if A,NB(H)A, N \in \mathcal{B}(\mathcal{H}) are polynomially isometric relative to the operator norm and NN is a normal operator whose spectrum neither disconnects the plane nor has interior, then AA is normal, while if the spectrum of NN is not of this form, then there always exists a non-normal operator BB such that BB and NN are polynomially isometric. Finally, we show that if AA and NN are compact operators with NN normal, and if AA and NN are polynomially isometric with respect to the (c,p)(c,p)-norm studied by Chan, Li and Tu, then AA is again normal.

Keywords

Cite

@article{arxiv.1908.07029,
  title  = {Operators which are polynomially isometric to a normal operator},
  author = {Laurent W. Marcoux and Yuanhang Zhang},
  journal= {arXiv preprint arXiv:1908.07029},
  year   = {2019}
}

Comments

submitted

R2 v1 2026-06-23T10:51:28.915Z