Operators on $C(\omega^\alpha)$ which do not preserve $C(\omega^\alpha)$
Functional Analysis
2008-02-03 v1
Abstract
It is shown that if are ordinals such that then there is an operator from onto itself such that if is a subspace of which is isomorphic to then the operator is not an isomorphism on This contrasts with a result of J. Bourgain that implies that there are uncountably many ordinals for which any operator from onto itself there is a subspace of which is isomorphic to on which the operator is an isomorphism.
Keywords
Cite
@article{arxiv.math/9610215,
title = {Operators on $C(\omega^\alpha)$ which do not preserve $C(\omega^\alpha)$},
author = {Dale E. Alspach},
journal= {arXiv preprint arXiv:math/9610215},
year = {2008}
}