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On the Nagata Problem

Algebraic Geometry 2013-05-09 v3

Abstract

Nagata has conjectured that the following statement (N_r) holds for all r10r\geq 10: (N_r) if P1,...PrP2P_1,...P_r \in {\mathbb P}^2 are generic points then any plane curve CC satisfies 1rmultPi(C)rdeg(C)\sum_1^r mult_{P_i}(C)\leq \sqrt{r} deg(C). Nagata proved (N_r) whenever rr is a perfect square. Here we prove (N_r) provided r=k2+α,1α2k,k3r=k^2+\alpha,1\leq\alpha\leq2k,k\geq 3 and either (i) α\alpha is odd and α2k\alpha\geq \sqrt{2k} or (ii) α\alpha is even and at lest 6, and the fractional part of r\sqrt{r} is at most 2(21)2(\sqrt{2}-1).

Keywords

Cite

@article{arxiv.math/9809101,
  title  = {On the Nagata Problem},
  author = {Ziv Ran},
  journal= {arXiv preprint arXiv:math/9809101},
  year   = {2013}
}

Comments

Withdrawn due to fatal error