English

On the Hamilton-Waterloo Problem with odd orders

Combinatorics 2015-11-24 v2

Abstract

Given non-negative integers v,m,n,α,βv, m, n, \alpha, \beta, the Hamilton-Waterloo problem asks for a factorization of the complete graph KvK_v into α\alpha CmC_m-factors and β\beta CnC_n-factors. Clearly, vv odd, n,m3n,m\geq 3, mvm\mid v, nvn\mid v and α+β=(v1)/2\alpha+\beta = (v-1)/2 are necessary conditions. To date results have only been found for specific values of mm and nn. In this paper we show that for any mm and nn the necessary conditions are sufficient when vv is a multiple of mnmn and v>mnv>mn, except possibly when β=1\beta=1 or 3, with five additional possible exceptions in (m,n,β)(m,n,\beta). For the case where v=mnv=mn we show sufficiency when β>(n+5)/2\beta > (n+5)/2 except possibly when (m,α)=(3,2)(m,\alpha) = (3,2), (3,4)(3,4), with seven further possible exceptions in (m,n,α,β)(m,n,\alpha,\beta). We also show that when nm3n\geq m\geq 3 are odd integers, the lexicographic product of CmC_m with the empty graph of order nn has a factorization into α\alpha CmC_m-factors and β\beta CnC_n-factors for every 0αn0\leq \alpha \leq n, β=nα\beta = n-\alpha, except possibly when α=2,4\alpha= 2,4, β=1,3\beta = 1, 3, with three additional possible exceptions in (m,n,α)(m,n,\alpha).

Keywords

Cite

@article{arxiv.1510.07079,
  title  = {On the Hamilton-Waterloo Problem with odd orders},
  author = {A. Burgess and P. Danziger and T. Traetta},
  journal= {arXiv preprint arXiv:1510.07079},
  year   = {2015}
}

Comments

39 pages

R2 v1 2026-06-22T11:27:54.555Z