English

On the Anti-Ramsey Number Under Edge Deletion

Combinatorics 2025-12-12 v3

Abstract

According to a study by Erd\H{o}s et al. in 1975, the anti-Ramsey number of a graph GG, denoted as AR(n,G)AR(n, G), is defined as the maximum number of colors that can be used in an edge-coloring of the complete graph KnK_n without creating a rainbow copy of GG. In this paper, we investigate the anti-Ramsey number under edge deletion and demonstrate that both decreasing and unchanging are possible outcomes. For three non-negative integers kk, tt, and nn, let G=kP4tP2G = kP_4 \cup tP_2. Let EE' be a subset of the edge set E(G)E(G) such that every endpoint of these edges has a degree of two in GG. We prove that if one of the conditions (i) tk+12t \geq k + 1 \geq 2 and n8k+2t4n \geq 8k + 2t - 4; (ii) k,t1k, t \geq 1 and n=4k+2tn = 4k + 2t; (iii) k=1k = 1, t1t \geq 1, and n2t+4n \geq 2t + 4, occurs then the behavior of the anti-Ramsey number remains consistent when the edges in EE' are removed from GG, i.e., AR(n,G)=AR(n,GE)AR(n, G) = AR(n, G - E'). However, this is not the case when k2k \geq 2, t=0t = 0, and n=4kn=4k. As a result, we calculate AR(kP4tP2)AR(kP_4 \cup tP_2) for the cases: (i) tk+12t \geq k + 1 \geq 2 and n8k+2t4n \geq 8k + 2t - 4; (ii) k,t1k, t \geq 1 and n=4k+2tn = 4k + 2t; (iii) k=1k = 1, t0t \geq 0, and n2t+4n \geq 2t + 4; (iv) k1k \geq 1, t=0t = 0, and n=4kn = 4k.

Keywords

Cite

@article{arxiv.2511.06034,
  title  = {On the Anti-Ramsey Number Under Edge Deletion},
  author = {Ali Ghalavand and Qing Jie and Zemin Jin and Xueliang Li and Linshu Pan},
  journal= {arXiv preprint arXiv:2511.06034},
  year   = {2025}
}