English

On Sum of a Polynomial Multiplied by Generalized Fibonacci Numbers

Number Theory 2025-05-12 v1

Abstract

Given that a,bNa,b\in\mathbb N, c0,c1Zc_0,c_1\in\mathbb Z, (c0,c1)(0,0)(c_0,c_1)\neq (0,0), and a generalized Fibonacci sequence (sn)n0(s_n)_{n\geq 0} where s0=c0s_0 = c_0, s1=c1s_1 = c_1, and sn+1=asn+bsn1s_{n+1}=as_{n}+bs_{n-1} for all positive integers nn. In this paper, we get the result that for every polynomials P(x)P(x) with real coefficients, we can always find three polynomials F1(x),G1(x),H1(x)F_1(x), G_1(x), H_1(x) (not necessarily distinct) with real coefficients satisfying the identity:   2k=1nP(k)sk1=F1(n)sn+1+G1(n)sn+H1(n),  nN\;2\sum_{k=1}^{n}P(k)s_{k-1} = F_1(n)s_{n+1} + G_1(n)s_n + H_1(n), \;\forall n\in\mathbb N. Furthermore, we serve two constraints for (sn)n0(s_n)_{n\geq 0}: one constraint implies that there are infinitely many triples (F1(x),G1(x),H1(x))(F_1(x), G_1(x), H_1(x)) satisfying the identity   2k=1nP(k)sk1=F1(n)sn+1+G1(n)sn+H1(n),  nN\;2\sum_{k=1}^{n}P(k)s_{k-1} = F_1(n)s_{n+1} + G_1(n)s_n + H_1(n), \;\forall n\in\mathbb N, while another constraint implies that there is only one triple (F1(x),G1(x),H1(x))(F_1(x), G_1(x), H_1(x)) satisfying the identity   2k=1nP(k)sk1=F1(n)sn+1+G1(n)sn+H1(n),  nN\;2\sum_{k=1}^{n}P(k)s_{k-1} = F_1(n)s_{n+1} + G_1(n)s_n + H_1(n), \;\forall n\in\mathbb N.

Keywords

Cite

@article{arxiv.2505.05734,
  title  = {On Sum of a Polynomial Multiplied by Generalized Fibonacci Numbers},
  author = {Ivan Hadinata},
  journal= {arXiv preprint arXiv:2505.05734},
  year   = {2025}
}

Comments

This is a preprint version, updated on 17 October 2024. The final version has been published in Jurnal Matematika Integratif (link: https://jurnal.unpad.ac.id/jmi/article/view/58753) with the new title "On Sums Involving Polynomials and Generalized Fibonacci Sequences"