English

On small deviations of stationary Gaussian processes and related analytic inequalities

Probability 2017-07-13 v2

Abstract

Let {Xj,jZ} \{X_j, j\in \Z\} be a Gaussian stationary sequence having a spectral function FF of infinite type. Then for all nn and z0z\ge 0,{supj=1nXjz}(z/G(f)z/G(f)ex2/2\ddx2π)n, \P\Big\{\sup_{j=1}^n |X_j|\le z \Big\}\le \Big(\int_{-z/\sqrt{G(f)}}^{z/\sqrt{G(f)}} e^{-x^2/2}\frac{\dd x}{\sqrt{2\pi}} \Big)^n, where G(f) G(f) is the geometric mean of the Radon Nycodim derivative of the absolutely continuous part ff of FF. The proof uses properties of finite Toeplitz forms. Let {X(t),tR} \{X(t), t\in \R\} be a sample continuous stationary Gaussian process with covariance function \g(u)\g(u) . We also show that there exists an absolute constant KK such that for all T>0T>0, a>0a>0 with T\e(a)T\ge \e(a), {sup0s,tTX(s)X(t)a}exp{KT\e(a)p(\e(a))},\P\Big\{\sup_{0\le s,t\le T} |X(s)-X(t)|\le a\Big\} \le \exp \Big \{-{KT \over \e(a) p(\e(a))}\Big\} , where \e(a)=min{b>0:\d(b)a}\e (a)= \min\big\{b>0: \d (b)\ge a\big\}, \d(b)=minu1{2(1\g((ub)),u1}\d (b)=\min_{u\ge 1}\{\sqrt{2(1-\g((ub))}, u\ge 1\}, and p(b)=1+j=22\g(jb)\g((j1)b)\g((j+1)b)2(1\g(b)) p(b) = 1+\sum_{j=2}^\infty {|2\g (jb)-\g ((j-1)b)-\g ((j+1)b)| \over 2(1-\g(b))}. The proof is based on some decoupling inequalities arising from Brascamp-Lieb inequality. Both approaches are developed and compared on examples. Several other related results are established.

Keywords

Cite

@article{arxiv.1104.2786,
  title  = {On small deviations of stationary Gaussian processes and related analytic inequalities},
  author = {Michel J. G. Weber},
  journal= {arXiv preprint arXiv:1104.2786},
  year   = {2017}
}