English

On groups with same number of centralizers

Group Theory 2023-05-30 v1

Abstract

In this paper, among other results, we give some sufficient conditions for every non-abelian subgroup of a group to be isoclinic with the group itself. It is also seen that under certain conditions, two groups have same number of element centralizers implies they are isoclinic. We prove that if GG is any group having 4,5,74, 5, 7 or 99 element centralizers and HH is any non-abelian subgroup of GG, then \Cent(G)=\Cent(H)\mid \Cent(G)\mid=\mid \Cent(H)\mid and GHC2,C3,C5 G' \cong H' \cong C_2, C_3, C_5 or C7C_7 respectively. Furthermore, it is proved that if GG is any group having n{4,5,6,7,9}n \in \lbrace 4, 5, 6, 7, 9 \rbrace element centralizers, then G=n2\mid G' \mid=n-2.

Keywords

Cite

@article{arxiv.2305.17621,
  title  = {On groups with same number of centralizers},
  author = {Sekhar Jyoti Baishya},
  journal= {arXiv preprint arXiv:2305.17621},
  year   = {2023}
}
R2 v1 2026-06-28T10:48:33.555Z